Hard GCSE Sampling Questions

Challenging, exam-style GCSE Sampling questions with worked solutions. Stretch yourself on the hardest sample proportion, scaling up to a population, estimation, estimating population size problems.

sample proportionscaling up to a populationestimationestimating population sizereverse scalingcomparing groups
GCSE Foundation34 questionsStep-by-step solutions
Question 1
5 markschallenging
There are 10001000 students at Ashfield School. A researcher wants to estimate the proportion of all 10001000 students who walk to school. The researcher chooses 44 students at random from a list of all 10001000 students. Which statement about this sample is correct?
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Worked solution

  1. Write down the population and the sample

    population=1000,sample=4\text{population} = 1000, \quad \text{sample} = 4

    The population is all 10001000 students at Ashfield School. The sample actually used contains 44 of them.

  2. Ask who could possibly have been chosen

    sampling frame=the whole population\text{sampling frame} = \text{the whole population}

    Every one of the 10001000 students could have been picked, so the sampling frame is the whole population.

  3. Ask who decided whether a member took part

    the researcher chose, at random\text{the researcher chose, at random}

    The researcher chose the members at random, so no one selected themselves into the sample.

  4. Ask whether the sample is big enough

    41000=0.004\frac{4}{1000} = 0.004

    A sample of just 44 out of 10001000 is a tiny fraction of the population. Even a perfectly random sample that small would swing wildly from one sample to the next, so no reliable estimate can come from it.

  5. Test the sample against the first thing that can go wrong: bias in the frame

    frame=populationno frame bias\text{frame} = \text{population} \Rightarrow \text{no frame bias}

    Everyone had a chance of being chosen, so there is no bias in the frame.

  6. Test the sample against the second thing that can go wrong: self-selection

    not self-selectedno volunteer bias\text{not self-selected} \Rightarrow \text{no volunteer bias}

    Nobody volunteered themselves, so volunteer bias is not the problem here.

  7. Test the sample against the third thing that can go wrong: size

    4 is far too small4 \text{ is far too small}

    A sample of 44 is far too small to say anything reliable about 10001000 students.

  8. Rule out the claim that the sample is bigger than the population

    4<10004 < 1000

    A sample is always part of the population, and 44 is indeed smaller than 10001000, so there is nothing wrong on that score.

  9. Rule out the claim that this is a census

    410004 \ne 1000

    A census asks every member of the population. Only 44 of the 10001000 students were asked, so this is a sample, not a census.

  10. Say what a good sample would look like

    random+whole population+large enough\text{random} + \text{whole population} + \text{large enough}

    A good sample is chosen at random from a list of all 10001000 students, is not made of volunteers, and is large enough that the proportion in it is a useful guide to the population.

  11. Say what a biased sample does to an estimate

    biased samplebiased estimate\text{biased sample} \Rightarrow \text{biased estimate}

    Scaling a biased sample up to the population does not fix the bias — it multiplies it. The estimate would be systematically wrong, and taking a bigger biased sample would not help either.

  12. Say what even a perfect sample cannot do

    samplecensus\text{sample} \ne \text{census}

    Even a fair random sample of 44 only gives an estimate: a different sample of 44 would give a slightly different answer. Only asking all 10001000 students would give the exact figure.

  13. Compare the five statements offered

    exactly one can be true\text{exactly one can be true}

    Each statement makes a different claim about this sample. Checking them against the population, the frame, the way members were chosen and the sample size leaves exactly one that survives.

  14. Pick the statement that survives

    The sample is far too small to be reliable\text{The sample is far too small to be reliable}

    The sample is far too small: only 44 of the 10001000 students were asked, so the estimate would not be reliable.

  15. State the answer

    The sample is far too small to be reliable\text{The sample is far too small to be reliable}

    The correct statement is: The sample is far too small: only 44 of the 10001000 students were asked, so the estimate would not be reliable.

Answer
The sample is far too small to be reliable\text{The sample is far too small to be reliable}
Question 2
5 markschallenging
A researcher chose 2020 households at random from the 15001500 households in the village of Wray and used the sample to estimate how many of the 15001500 households recycle glass. Which of these changes would most improve the estimate?
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Worked solution

  1. Write down what is already right about the sample

    20 chosen at random from 150020 \text{ chosen at random from } 1500

    The 2020 households were chosen at random from all 15001500, so the sample is not biased. Whatever is improved must not spoil that.

  2. Say what is still wrong with the sample

    201500 is a small fraction\frac{20}{1500} \text{ is a small fraction}

    Only 2020 of the 15001500 households were asked, so the estimate could easily be a little way out. The weakness is the size of the sample, not the way it was chosen.

  3. Say what a larger random sample does

    20250less variation20 \rightarrow 250 \Rightarrow \text{less variation}

    A random sample of 250250 varies less from one sample to the next than a sample of 2020 does, so its proportion is more likely to be close to the true proportion in the population.

  4. Rule out taking a smaller sample

    10<2010 < 20

    A sample of 1010 is smaller still, so its estimate would swing about even more. Smaller is worse, not better.

  5. Rule out asking the same people again

    202020 \rightarrow 20

    Asking the same 2020 households a second time adds no new households at all, so it gives no new information about the ones who were never asked.

  6. Rule out the two biased methods

    biased framebiased estimate\text{biased frame} \Rightarrow \text{biased estimate}

    Asking 250250 households at the village shop, or using online volunteers, would make the sample bigger but no longer random: some members could not be chosen at all. A bigger biased sample is worse than a smaller fair one, because it gives a confident answer that is systematically wrong.

  7. Say what the improvement does not do

    estimateexact value\text{estimate} \ne \text{exact value}

    Even 250250 households chosen at random still leaves 12501250 households unasked, so the answer stays an estimate. A larger sample makes the estimate more reliable; it does not make it exact.

  8. Say what would make it exact

    ask all 1500census\text{ask all } 1500 \Rightarrow \text{census}

    Only asking every one of the 15001500 households — a census — gives the exact number who recycle glass, and that is usually far too slow and expensive to do.

  9. Compare the five suggestions

    keep random+increase n\text{keep random} + \text{increase } n

    The best change is the one that keeps the sample random and covering the whole population, and increases the number of members asked. Only one of the five does both.

  10. Check the winning option keeps the sample random

    250 at random from all 1500250 \text{ at random from all } 1500

    The larger sample is still chosen at random from all 15001500 households, so it is still unbiased — just more reliable.

  11. Check the winning option really is larger

    250>20250 > 20

    250250 is bigger than 2020, so this really is a larger sample.

  12. Say why bias cannot be cured by size

    biasnoise\text{bias} \ne \text{noise}

    A small random sample is noisy but fair; a large biased sample is precise but wrong. Increasing the size of a biased sample only makes you more confident in the wrong answer, which is why the biased options are not improvements.

  13. Say how the larger sample should actually be taken

    number the 1500, pick 250 at random\text{number the } 1500 \text{, pick } 250 \text{ at random}

    Number all 15001500 households, then use random numbers to pick 250250 of them. That is what "chosen at random from all" means in practice.

  14. Summarise the rule

    larger+randommore reliable\text{larger} + \text{random} \Rightarrow \text{more reliable}

    To improve an estimate from a sample: keep it random, keep it covering the whole population, and make it bigger.

  15. State the answer

    250 at random from all 1500250 \text{ at random from all } 1500

    The change that would most improve the estimate is: Take a larger random sample, for example 250250 households chosen at random from all 15001500 households.

Answer
Take a larger random sample of 250 from all 1500\text{Take a larger random sample of } 250 \text{ from all } 1500
Question 3
5 markschallenging
A researcher chose 4040 members at random from the 20002000 members at Brookside Library and used the sample to estimate how many of the 20002000 members borrow e-books. Which of these changes would most improve the estimate?
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Worked solution

  1. Write down what is already right about the sample

    40 chosen at random from 200040 \text{ chosen at random from } 2000

    The 4040 members were chosen at random from all 20002000, so the sample is not biased. Whatever is improved must not spoil that.

  2. Say what is still wrong with the sample

    402000 is a small fraction\frac{40}{2000} \text{ is a small fraction}

    Only 4040 of the 20002000 members were asked, so the estimate could easily be a little way out. The weakness is the size of the sample, not the way it was chosen.

  3. Say what a larger random sample does

    40400less variation40 \rightarrow 400 \Rightarrow \text{less variation}

    A random sample of 400400 varies less from one sample to the next than a sample of 4040 does, so its proportion is more likely to be close to the true proportion in the population.

  4. Rule out taking a smaller sample

    15<4015 < 40

    A sample of 1515 is smaller still, so its estimate would swing about even more. Smaller is worse, not better.

  5. Rule out asking the same people again

    404040 \rightarrow 40

    Asking the same 4040 members a second time adds no new members at all, so it gives no new information about the ones who were never asked.

  6. Rule out the two biased methods

    biased framebiased estimate\text{biased frame} \Rightarrow \text{biased estimate}

    Asking 400400 members at the reading group, or using online volunteers, would make the sample bigger but no longer random: some members could not be chosen at all. A bigger biased sample is worse than a smaller fair one, because it gives a confident answer that is systematically wrong.

  7. Say what the improvement does not do

    estimateexact value\text{estimate} \ne \text{exact value}

    Even 400400 members chosen at random still leaves 16001600 members unasked, so the answer stays an estimate. A larger sample makes the estimate more reliable; it does not make it exact.

  8. Say what would make it exact

    ask all 2000census\text{ask all } 2000 \Rightarrow \text{census}

    Only asking every one of the 20002000 members — a census — gives the exact number who borrow e-books, and that is usually far too slow and expensive to do.

  9. Compare the five suggestions

    keep random+increase n\text{keep random} + \text{increase } n

    The best change is the one that keeps the sample random and covering the whole population, and increases the number of members asked. Only one of the five does both.

  10. Check the winning option keeps the sample random

    400 at random from all 2000400 \text{ at random from all } 2000

    The larger sample is still chosen at random from all 20002000 members, so it is still unbiased — just more reliable.

  11. Check the winning option really is larger

    400>40400 > 40

    400400 is bigger than 4040, so this really is a larger sample.

  12. Say why bias cannot be cured by size

    biasnoise\text{bias} \ne \text{noise}

    A small random sample is noisy but fair; a large biased sample is precise but wrong. Increasing the size of a biased sample only makes you more confident in the wrong answer, which is why the biased options are not improvements.

  13. Say how the larger sample should actually be taken

    number the 2000, pick 400 at random\text{number the } 2000 \text{, pick } 400 \text{ at random}

    Number all 20002000 members, then use random numbers to pick 400400 of them. That is what "chosen at random from all" means in practice.

  14. Summarise the rule

    larger+randommore reliable\text{larger} + \text{random} \Rightarrow \text{more reliable}

    To improve an estimate from a sample: keep it random, keep it covering the whole population, and make it bigger.

  15. State the answer

    400 at random from all 2000400 \text{ at random from all } 2000

    The change that would most improve the estimate is: Take a larger random sample, for example 400400 members chosen at random from all 20002000 members.

Answer
Take a larger random sample of 400 from all 2000\text{Take a larger random sample of } 400 \text{ from all } 2000
Question 4
6 markschallenging
There are 900900 students at Hillside School. In a random sample of 2020 students, 1313 own a bicycle and the other 77 do not. Estimate how many more of the 900900 students own a bicycle than do not.
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Worked solution

  1. Write down what the sample found

    13+7=2013 + 7 = 20

    Of the 2020 students in the sample, 1313 own a bicycle and 77 do not. The two groups add up to the whole sample, which is a useful check.

  2. Write each group as a fraction of the sample

    1320,720\frac{13}{20}, \quad \frac{7}{20}

    1320\frac{13}{20} of the sample own a bicycle and 720\frac{7}{20} do not.

  3. Check the two fractions add to one

    1320+720=2020=1\frac{13}{20} + \frac{7}{20} = \frac{20}{20} = 1

    Every member of the sample is in exactly one of the two groups, so the two proportions must add up to 11.

  4. Simplify the fraction for the group you want

    1320=1320\frac{13}{20} = \frac{13}{20}

    Dividing top and bottom by 11 gives 1320\frac{13}{20}.

  5. State the assumption you are making

    sample proportion=population proportion\text{sample proportion} = \text{population proportion}

    Assume the random sample is representative of the whole population.

  6. Estimate the number in the population who do

    1320×900=585\frac{13}{20} \times 900 = 585

    About 585585 of the 900900 students own a bicycle.

  7. Estimate the number in the population who do not

    720×900=315\frac{7}{20} \times 900 = 315

    About 315315 of the 900900 students do not.

  8. Check the two estimates add to the whole population

    585+315=900585 + 315 = 900

    Every one of the 900900 students is in one group or the other, and the two estimates do add to 900900 — so the scaling is consistent.

  9. Subtract to find the difference

    585315=270585 - 315 = 270

    About 270270 more students own a bicycle than do not.

  10. Check the difference a second way

    13720×900=620×900=270\frac{13 - 7}{20} \times 900 = \frac{6}{20} \times 900 = 270

    The sample has 137=613 - 7 = 6 more in one group than the other, which is 620\frac{6}{20} of the sample. Scaling that fraction straight up to 900900 gives 270270 — the same answer from a different route.

  11. Check the answer is sensible

    0<270<9000 < 270 < 900

    The difference must be smaller than the whole population, and it is.

  12. Say why this is only an estimate

    samplepopulation\text{sample} \ne \text{population}

    Only 2020 of the 900900 students were actually asked. A different random sample of 2020 would almost certainly contain a different number, so the answer is an estimate, not an exact figure.

  13. Say how the estimate could be made more reliable

    20larger sample20 \rightarrow \text{larger sample}

    A larger random sample varies less from one sample to the next, so it is more likely to represent the whole population. Asking more people (still chosen at random) would make the estimate more reliable.

  14. Say what would make the estimate worse

    biased samplebiased estimate\text{biased sample} \Rightarrow \text{biased estimate}

    If the students had not been chosen at random — for example if only one year group, or only the people who chose to reply, had been used — the sample would be biased and scaling it up would give a misleading answer.

  15. State the answer in context

    about 270 more students\text{about } 270 \text{ more students}

    About 270270 more of the 900900 students own a bicycle than do not.

Answer
about 270 more students\text{about } 270 \text{ more students}
Question 5
6 markschallenging
There are 12001200 adults in the town of Kelby. In a random sample of 5050 adults, 3232 read a newspaper and the other 1818 do not. Estimate how many more of the 12001200 adults read a newspaper than do not.
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Worked solution

  1. Write down what the sample found

    32+18=5032 + 18 = 50

    Of the 5050 adults in the sample, 3232 read a newspaper and 1818 do not. The two groups add up to the whole sample, which is a useful check.

  2. Write each group as a fraction of the sample

    3250,1850\frac{32}{50}, \quad \frac{18}{50}

    3250\frac{32}{50} of the sample read a newspaper and 1850\frac{18}{50} do not.

  3. Check the two fractions add to one

    3250+1850=5050=1\frac{32}{50} + \frac{18}{50} = \frac{50}{50} = 1

    Every member of the sample is in exactly one of the two groups, so the two proportions must add up to 11.

  4. Simplify the fraction for the group you want

    3250=1625\frac{32}{50} = \frac{16}{25}

    Dividing top and bottom by 22 gives 1625\frac{16}{25}.

  5. State the assumption you are making

    sample proportion=population proportion\text{sample proportion} = \text{population proportion}

    Assume the random sample is representative of the whole population.

  6. Estimate the number in the population who do

    3250×1200=768\frac{32}{50} \times 1200 = 768

    About 768768 of the 12001200 adults read a newspaper.

  7. Estimate the number in the population who do not

    1850×1200=432\frac{18}{50} \times 1200 = 432

    About 432432 of the 12001200 adults do not.

  8. Check the two estimates add to the whole population

    768+432=1200768 + 432 = 1200

    Every one of the 12001200 adults is in one group or the other, and the two estimates do add to 12001200 — so the scaling is consistent.

  9. Subtract to find the difference

    768432=336768 - 432 = 336

    About 336336 more adults read a newspaper than do not.

  10. Check the difference a second way

    321850×1200=1450×1200=336\frac{32 - 18}{50} \times 1200 = \frac{14}{50} \times 1200 = 336

    The sample has 3218=1432 - 18 = 14 more in one group than the other, which is 1450\frac{14}{50} of the sample. Scaling that fraction straight up to 12001200 gives 336336 — the same answer from a different route.

  11. Check the answer is sensible

    0<336<12000 < 336 < 1200

    The difference must be smaller than the whole population, and it is.

  12. Say why this is only an estimate

    samplepopulation\text{sample} \ne \text{population}

    Only 5050 of the 12001200 adults were actually asked. A different random sample of 5050 would almost certainly contain a different number, so the answer is an estimate, not an exact figure.

  13. Say how the estimate could be made more reliable

    50larger sample50 \rightarrow \text{larger sample}

    A larger random sample varies less from one sample to the next, so it is more likely to represent the whole population. Asking more people (still chosen at random) would make the estimate more reliable.

  14. Say what would make the estimate worse

    biased samplebiased estimate\text{biased sample} \Rightarrow \text{biased estimate}

    If the adults had not been chosen at random — for example if only one year group, or only the people who chose to reply, had been used — the sample would be biased and scaling it up would give a misleading answer.

  15. State the answer in context

    about 336 more adults\text{about } 336 \text{ more adults}

    About 336336 more of the 12001200 adults read a newspaper than do not.

Answer
about 336 more adults\text{about } 336 \text{ more adults}

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