Hard GCSE Charts and tables Questions

Challenging, exam-style GCSE Charts and tables questions with worked solutions. Stretch yourself on the hardest reading a bar chart, total frequency, percentage of a total, reading a pictogram problems.

reading a bar charttotal frequencypercentage of a totalreading a pictogramusing a keymissing row
GCSE Foundation34 questionsStep-by-step solutions
Question 1
5 markschallenging
The bar chart shows the number of cakes for each day. Which of these statements about the bar chart is correct?
Show worked solution

Worked solution

  1. Read the scale on the vertical axis

    1 square=1 unit of frequency1 \text{ square} = 1 \text{ unit of frequency}

    Before reading anything off a chart, check what one square on the frequency axis is worth. Here the numbered ticks go up in equal steps, so the height of a bar is read straight off the axis.

  2. Read the bar for Monday

    Monday=5\text{Monday} = 5

    The top of the Monday bar lines up with 55 on the frequency axis, so there are 55 cakes for Monday.

  3. Read the bar for Tuesday

    Tuesday=11\text{Tuesday} = 11

    The top of the Tuesday bar lines up with 1111 on the frequency axis, so there are 1111 cakes for Tuesday.

  4. Read the bar for Wednesday

    Wednesday=14\text{Wednesday} = 14

    The top of the Wednesday bar lines up with 1414 on the frequency axis, so there are 1414 cakes for Wednesday.

  5. Read the bar for Thursday

    Thursday=9\text{Thursday} = 9

    The top of the Thursday bar lines up with 99 on the frequency axis, so there are 99 cakes for Thursday.

  6. Read the bar for Friday

    Friday=5\text{Friday} = 5

    The top of the Friday bar lines up with 55 on the frequency axis, so there are 55 cakes for Friday.

  7. Work out the total

    5+11+14+9+5=445 + 11 + 14 + 9 + 5 = 44

    Several of the statements talk about the total, so add all the frequencies: there are 4444 cakes altogether.

  8. Note the biggest and the smallest bar

    max=14 (Wednesday),min=5 (Monday)\max = 14 \ (\text{Wednesday}), \quad \min = 5 \ (\text{Monday})

    Statements about "the most" and "the fewest" can be settled straight away: the tallest bar is Wednesday and the shortest is Monday.

  9. Test the statement "Thursday has 4 more cakes than Monday."

    Thursday has 4 more cakes than Monday \text{Thursday has 4 more cakes than Monday} \ \checkmark

    Check it against the data (Monday=5,Thursday=9\text{Monday} = 5, \text{Thursday} = 9). It is true, so this is the correct statement.

  10. Test the statement "Thursday has twice as many cakes as Monday."

    Thursday has twice as many cakes as Monday ×\text{Thursday has twice as many cakes as Monday} \ \times

    Check it against the data (Monday=5,Thursday=9\text{Monday} = 5, \text{Thursday} = 9). It does not match the data, so this statement is wrong.

  11. Test the statement "Monday has the fewest cakes."

    Monday has the fewest cakes ×\text{Monday has the fewest cakes} \ \times

    Check it against the data (Monday=5\text{Monday} = 5). It does not match the data, so this statement is wrong.

  12. Test the statement "The total number of cakes is 41."

    The total number of cakes is 41 ×\text{The total number of cakes is 41} \ \times

    Check it against the data (total = 44). It does not match the data, so this statement is wrong.

  13. Test the statement "Wednesday and Friday have the same number of cakes."

    Wednesday and Friday have the same number of cakes ×\text{Wednesday and Friday have the same number of cakes} \ \times

    Check it against the data (Wednesday=14,Friday=5\text{Wednesday} = 14, \text{Friday} = 5). It does not match the data, so this statement is wrong.

  14. Count how many statements are true

    true statements=1\text{true statements} = 1

    Exactly one of the five statements matches the data. If two had matched, the question would have been faulty — checking every option is what proves the answer, not just stopping at the first one that looks right.

  15. Write down the statement that survived

    correct: Thursday has 4 more cakes than Monday\text{correct: Thursday has 4 more cakes than Monday}

    Only one of the five statements matches the data, so the answer is "Thursday has 4 more cakes than Monday."

Answer
Thursday has 4 more cakes than Monday\text{Thursday has 4 more cakes than Monday}
Question 2
5 markschallenging
The bar chart shows the number of visitors for each month. Which of these statements about the bar chart is correct?
Show worked solution

Worked solution

  1. Read the scale on the vertical axis

    1 square=1 unit of frequency1 \text{ square} = 1 \text{ unit of frequency}

    Before reading anything off a chart, check what one square on the frequency axis is worth. Here the numbered ticks go up in equal steps, so the height of a bar is read straight off the axis.

  2. Read the bar for January

    January=8\text{January} = 8

    The top of the January bar lines up with 88 on the frequency axis, so there are 88 visitors for January.

  3. Read the bar for February

    February=11\text{February} = 11

    The top of the February bar lines up with 1111 on the frequency axis, so there are 1111 visitors for February.

  4. Read the bar for March

    March=5\text{March} = 5

    The top of the March bar lines up with 55 on the frequency axis, so there are 55 visitors for March.

  5. Read the bar for April

    April=12\text{April} = 12

    The top of the April bar lines up with 1212 on the frequency axis, so there are 1212 visitors for April.

  6. Read the bar for May

    May=11\text{May} = 11

    The top of the May bar lines up with 1111 on the frequency axis, so there are 1111 visitors for May.

  7. Work out the total

    8+11+5+12+11=478 + 11 + 5 + 12 + 11 = 47

    Several of the statements talk about the total, so add all the frequencies: there are 4747 visitors altogether.

  8. Note the biggest and the smallest bar

    max=12 (April),min=5 (March)\max = 12 \ (\text{April}), \quad \min = 5 \ (\text{March})

    Statements about "the most" and "the fewest" can be settled straight away: the tallest bar is April and the shortest is March.

  9. Test the statement "January has more visitors than March."

    January has more visitors than March \text{January has more visitors than March} \ \checkmark

    Check it against the data (January=8,March=5\text{January} = 8, \text{March} = 5). It is true, so this is the correct statement.

  10. Test the statement "May has twice as many visitors as March."

    May has twice as many visitors as March ×\text{May has twice as many visitors as March} \ \times

    Check it against the data (March=5,May=11\text{March} = 5, \text{May} = 11). It does not match the data, so this statement is wrong.

  11. Test the statement "January and March have the same number of visitors."

    January and March have the same number of visitors ×\text{January and March have the same number of visitors} \ \times

    Check it against the data (January=8,March=5\text{January} = 8, \text{March} = 5). It does not match the data, so this statement is wrong.

  12. Test the statement "The total number of visitors is 45."

    The total number of visitors is 45 ×\text{The total number of visitors is 45} \ \times

    Check it against the data (total = 47). It does not match the data, so this statement is wrong.

  13. Test the statement "March has the most visitors."

    March has the most visitors ×\text{March has the most visitors} \ \times

    Check it against the data (March=5\text{March} = 5). It does not match the data, so this statement is wrong.

  14. Count how many statements are true

    true statements=1\text{true statements} = 1

    Exactly one of the five statements matches the data. If two had matched, the question would have been faulty — checking every option is what proves the answer, not just stopping at the first one that looks right.

  15. Write down the statement that survived

    correct: January has more visitors than March\text{correct: January has more visitors than March}

    Only one of the five statements matches the data, so the answer is "January has more visitors than March."

Answer
January has more visitors than March\text{January has more visitors than March}
Question 3
5 markschallenging
The bar chart shows the number of tickets for each film. Which of these statements about the bar chart is correct?
Show worked solution

Worked solution

  1. Read the scale on the vertical axis

    1 square=1 unit of frequency1 \text{ square} = 1 \text{ unit of frequency}

    Before reading anything off a chart, check what one square on the frequency axis is worth. Here the numbered ticks go up in equal steps, so the height of a bar is read straight off the axis.

  2. Read the bar for Comedy

    Comedy=6\text{Comedy} = 6

    The top of the Comedy bar lines up with 66 on the frequency axis, so there are 66 tickets for Comedy.

  3. Read the bar for Action

    Action=4\text{Action} = 4

    The top of the Action bar lines up with 44 on the frequency axis, so there are 44 tickets for Action.

  4. Read the bar for Horror

    Horror=6\text{Horror} = 6

    The top of the Horror bar lines up with 66 on the frequency axis, so there are 66 tickets for Horror.

  5. Read the bar for Cartoon

    Cartoon=3\text{Cartoon} = 3

    The top of the Cartoon bar lines up with 33 on the frequency axis, so there are 33 tickets for Cartoon.

  6. Read the bar for Drama

    Drama=8\text{Drama} = 8

    The top of the Drama bar lines up with 88 on the frequency axis, so there are 88 tickets for Drama.

  7. Work out the total

    6+4+6+3+8=276 + 4 + 6 + 3 + 8 = 27

    Several of the statements talk about the total, so add all the frequencies: there are 2727 tickets altogether.

  8. Note the biggest and the smallest bar

    max=8 (Drama),min=3 (Cartoon)\max = 8 \ (\text{Drama}), \quad \min = 3 \ (\text{Cartoon})

    Statements about "the most" and "the fewest" can be settled straight away: the tallest bar is Drama and the shortest is Cartoon.

  9. Test the statement "Horror has twice as many tickets as Cartoon."

    Horror has twice as many tickets as Cartoon \text{Horror has twice as many tickets as Cartoon} \ \checkmark

    Check it against the data (Horror=6,Cartoon=3\text{Horror} = 6, \text{Cartoon} = 3). It is true, so this is the correct statement.

  10. Test the statement "Action has 3 more tickets than Horror."

    Action has 3 more tickets than Horror ×\text{Action has 3 more tickets than Horror} \ \times

    Check it against the data (Action=4,Horror=6\text{Action} = 4, \text{Horror} = 6). It does not match the data, so this statement is wrong.

  11. Test the statement "Cartoon has the most tickets."

    Cartoon has the most tickets ×\text{Cartoon has the most tickets} \ \times

    Check it against the data (Cartoon=3\text{Cartoon} = 3). It does not match the data, so this statement is wrong.

  12. Test the statement "Cartoon and Drama have the same number of tickets."

    Cartoon and Drama have the same number of tickets ×\text{Cartoon and Drama have the same number of tickets} \ \times

    Check it against the data (Cartoon=3,Drama=8\text{Cartoon} = 3, \text{Drama} = 8). It does not match the data, so this statement is wrong.

  13. Test the statement "The total number of tickets is 30."

    The total number of tickets is 30 ×\text{The total number of tickets is 30} \ \times

    Check it against the data (total = 27). It does not match the data, so this statement is wrong.

  14. Count how many statements are true

    true statements=1\text{true statements} = 1

    Exactly one of the five statements matches the data. If two had matched, the question would have been faulty — checking every option is what proves the answer, not just stopping at the first one that looks right.

  15. Write down the statement that survived

    correct: Horror has twice as many tickets as Cartoon\text{correct: Horror has twice as many tickets as Cartoon}

    Only one of the five statements matches the data, so the answer is "Horror has twice as many tickets as Cartoon."

Answer
Horror has twice as many tickets as Cartoon\text{Horror has twice as many tickets as Cartoon}
Question 4
6 markschallenging
The table shows the number of goals for each team. The frequency for City is missing from the table. Altogether there are 2525 goals. What percentage of the goals are for City?
Show worked solution

Worked solution

  1. Say what is known and what is not

    City=?,total=25\text{City} = ?, \quad \text{total} = 25

    The table has a gap where the City frequency should be, but the total is given, so the gap can be filled by subtraction.

  2. Write down the frequencies that ARE given

    Rovers=2,United=8,Albion=3\text{Rovers} = 2, \quad \text{United} = 8, \quad \text{Albion} = 3

    These are the rows the table does show.

  3. Add the known frequencies

    2+8+3=132 + 8 + 3 = 13

    The rows that are filled in account for 1313 goals.

  4. Use the fact that the rows must add to the total

    City+13=25\text{City} + 13 = 25

    Every one of the 2525 goals is in exactly one row, so the missing frequency plus 1313 must come to 2525.

  5. Solve for the missing frequency

    City=2513=12\text{City} = 25 - 13 = 12

    Subtracting gives 1212, so there are 1212 goals for City.

  6. Fill the gap in the table

    Rovers=2,United=8,City=12,Albion=3\text{Rovers} = 2, \quad \text{United} = 8, \quad \text{City} = 12, \quad \text{Albion} = 3

    The table is now complete and every later step can use it.

  7. Check the completed table

    2+8+12+3=252 + 8 + 12 + 3 = 25

    Adding the completed column gives 2525, which matches the total in the question.

  8. Say what the percentage is out of

    out of=25\text{out of} = 25

    A percentage is always out of the whole data set, which is all 2525 goals — not out of the 1313 that were already in the table.

  9. Write the amount as a fraction of the total

    1225\frac{12}{25}

    "1212 out of 2525" is the fraction 1225\frac{12}{25}.

  10. Simplify the fraction

    1225=1225\frac{12}{25} = \frac{12}{25}

    Dividing top and bottom by 11 gives 1225\frac{12}{25}.

  11. Turn the fraction into a percentage

    1225×100\frac{12}{25} \times 100

    A percentage is a fraction out of 100100, so multiply by 100100.

  12. Do the multiplication

    12×10025=120025=48\frac{12 \times 100}{25} = \frac{1200}{25} = 48

    1200÷25=481200 \div 25 = 48.

  13. Check by reversing the calculation

    48% of 25=48100×25=1248\% \text{ of } 25 = \frac{48}{100} \times 25 = 12

    48%48\% of 2525 gives back 1212, the missing frequency, so the percentage is right.

  14. Check the percentages of all the rows

    8+32+48+12=1008 + 32 + 48 + 12 = 100

    Doing the same for every row gives percentages that add up to 100%100\%, as they must.

  15. State the answer

    48%48\%

    So 48%48\% of the goals are for City.

Answer
48%48\%
Question 5
6 markschallenging
The table shows the number of cars for each colour. The frequency for Black is missing from the table. Altogether there are 5050 cars. What percentage of the cars are for Black?
Show worked solution

Worked solution

  1. Say what is known and what is not

    Black=?,total=50\text{Black} = ?, \quad \text{total} = 50

    The table has a gap where the Black frequency should be, but the total is given, so the gap can be filled by subtraction.

  2. Write down the frequencies that ARE given

    Red=11,Blue=6,White=16\text{Red} = 11, \quad \text{Blue} = 6, \quad \text{White} = 16

    These are the rows the table does show.

  3. Add the known frequencies

    11+6+16=3311 + 6 + 16 = 33

    The rows that are filled in account for 3333 cars.

  4. Use the fact that the rows must add to the total

    Black+33=50\text{Black} + 33 = 50

    Every one of the 5050 cars is in exactly one row, so the missing frequency plus 3333 must come to 5050.

  5. Solve for the missing frequency

    Black=5033=17\text{Black} = 50 - 33 = 17

    Subtracting gives 1717, so there are 1717 cars for Black.

  6. Fill the gap in the table

    Red=11,Blue=6,White=16,Black=17\text{Red} = 11, \quad \text{Blue} = 6, \quad \text{White} = 16, \quad \text{Black} = 17

    The table is now complete and every later step can use it.

  7. Check the completed table

    11+6+16+17=5011 + 6 + 16 + 17 = 50

    Adding the completed column gives 5050, which matches the total in the question.

  8. Say what the percentage is out of

    out of=50\text{out of} = 50

    A percentage is always out of the whole data set, which is all 5050 cars — not out of the 3333 that were already in the table.

  9. Write the amount as a fraction of the total

    1750\frac{17}{50}

    "1717 out of 5050" is the fraction 1750\frac{17}{50}.

  10. Simplify the fraction

    1750=1750\frac{17}{50} = \frac{17}{50}

    Dividing top and bottom by 11 gives 1750\frac{17}{50}.

  11. Turn the fraction into a percentage

    1750×100\frac{17}{50} \times 100

    A percentage is a fraction out of 100100, so multiply by 100100.

  12. Do the multiplication

    17×10050=170050=34\frac{17 \times 100}{50} = \frac{1700}{50} = 34

    1700÷50=341700 \div 50 = 34.

  13. Check by reversing the calculation

    34% of 50=34100×50=1734\% \text{ of } 50 = \frac{34}{100} \times 50 = 17

    34%34\% of 5050 gives back 1717, the missing frequency, so the percentage is right.

  14. Check the percentages of all the rows

    22+12+32+34=10022 + 12 + 32 + 34 = 100

    Doing the same for every row gives percentages that add up to 100%100\%, as they must.

  15. State the answer

    34%34\%

    So 34%34\% of the cars are for Black.

Answer
34%34\%

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