GCSE Sampling and convergence Practice Questions

Free GCSE Sampling and convergence practice questions with full step-by-step worked solutions. Covers relative frequency, experimental probability, simplifying fractions, expected frequency. Practise exam-style problems and check your method.

relative frequencyexperimental probabilitysimplifying fractionsexpected frequencyprobability x trialsobserved frequency
GCSE Foundation70 questionsStep-by-step solutions
Question 1
1 markeasy
A drawing pin is dropped 200200 times. It lands point up 7474 times. Work out the relative frequency of landing point up. Give your answer as a decimal.
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Worked solution

  1. Write down the rule for relative frequency

    relative frequency=number of successesnumber of trials\text{relative frequency} = \frac{\text{number of successes}}{\text{number of trials}}

    Relative frequency (experimental probability) is worked out from the results of an experiment: how many times the event happened, divided by how many times the experiment was carried out.

  2. Substitute the results of the experiment

    relative frequency=74200\text{relative frequency} = \frac{74}{200}

    The event landing point up happened 7474 times in 200200 trials, so the relative frequency is 74200\frac{74}{200}.

  3. Work out the answer

    74200=0.37\frac{74}{200} = 0.37

    Dividing 7474 by 200200 gives 0.370.37. This is an ESTIMATE of the probability of landing point up, not the probability itself.

Answer
0.370.37
Question 2
1 markeasy
A fair spinner has 55 equal sections. 11 of the sections is red. The spinner is spun 4040 times, and then it is spun 40004000 times. Which statement about the relative frequency of red is correct?
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Worked solution

  1. Work out the theoretical probability from the equally likely outcomes

    P(red)=15P(\text{red}) = \frac{1}{5}

    Because the spinner has 55 equal sections, so all 55 outcomes are equally likely, and 11 of them is red, the theoretical probability of red is 15\frac{1}{5}. This value is fixed: it does not depend on how many trials are carried out.

  2. Say what a larger sample does

    more trialsthe estimate settles\text{more trials} \Rightarrow \text{the estimate settles}

    As the number of spins grows, the relative frequency settles down: it varies less and less, and it TENDS towards 15\frac{1}{5}. That is why 40004000 spins is worth far more than 4040 spins.

  3. State the answer

    Usually closer, but not certain\text{Usually closer, but not certain}

    The correct statement is: The relative frequency of red after 40004000 spins will usually be closer to the theoretical probability 15\frac{1}{5} than the relative frequency after 4040 spins, but it is not certain to be closer.

Answer
Usually closer, but not certain\text{Usually closer, but not certain}
Question 3
2 marksintermediate
A fair spinner has 88 equal sections. 33 of the sections are green. The spinner is spun 6060 times, and then it is spun 60006000 times. Which statement about the relative frequency of green is correct?
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Worked solution

  1. Work out the theoretical probability from the equally likely outcomes

    P(green)=38P(\text{green}) = \frac{3}{8}

    Because the spinner has 88 equal sections, so all 88 outcomes are equally likely, and 33 of them are green, the theoretical probability of green is 38\frac{3}{8}. This value is fixed: it does not depend on how many trials are carried out.

  2. Say what each relative frequency is

    relative frequencyP(event)\text{relative frequency} \approx P(\text{event})

    Each experiment produces a relative frequency - successes divided by trials - and each one is only an ESTIMATE of 38\frac{3}{8}.

  3. Say what a larger sample does

    more trialsthe estimate settles\text{more trials} \Rightarrow \text{the estimate settles}

    As the number of spins grows, the relative frequency settles down: it varies less and less, and it TENDS towards 38\frac{3}{8}. That is why 60006000 spins is worth far more than 6060 spins.

  4. Say what a larger sample does NOT do

    tendency, not a guarantee\text{tendency}, \ \text{not a guarantee}

    It does not guarantee anything. A run of 6060 spins could, by luck, land closer to 38\frac{3}{8} than a run of 60006000 spins. "Usually closer" is true; "certainly closer" is false.

  5. Rule out the idea that the estimate becomes exact

    relative frequency38 exactly\text{relative frequency} \ne \frac{3}{8} \text{ exactly}

    Even after 60006000 spins the relative frequency will almost certainly not be exactly 38\frac{3}{8}. It gets close; it does not land on it.

  6. State the answer

    Usually closer, but not certain\text{Usually closer, but not certain}

    The correct statement is: The relative frequency of green after 60006000 spins will usually be closer to the theoretical probability 38\frac{3}{8} than the relative frequency after 6060 spins, but it is not certain to be closer.

Answer
Usually closer, but not certain\text{Usually closer, but not certain}
Question 4
3 markshard
A fair coin is thrown many times. The number of heads is counted at four stages. After 2020 throws there had been 1414 heads. After 200200 throws there had been 118118 heads. After 10001000 throws there had been 528528 heads. After 50005000 throws there had been 25102510 heads. Which statement is best supported by these results?
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Worked solution

  1. Read what the table is recording

    (20,14),(200,118),(1000,528),(5000,2510)(20, 14), \quad (200, 118), \quad (1000, 528), \quad (5000, 2510)

    Each pair is a running total: the number of throws so far, and the number of heads in all of those throws.

  2. Work out the theoretical probability from the equally likely outcomes

    P(heads)=12P(\text{heads}) = \frac{1}{2}

    Because a fair coin has 22 equally likely outcomes, heads and tails, and 11 of them is heads, the theoretical probability of heads is 12=0.5\frac{1}{2} = 0.5. It is fixed, and no experiment can change it.

  3. Work out the relative frequency at each stage

    1420=0.7,118200=0.59,5281000=0.528,25105000=0.502\frac{14}{20} = 0.7, \quad \frac{118}{200} = 0.59, \quad \frac{528}{1000} = 0.528, \quad \frac{2510}{5000} = 0.502

    Each stage gives an estimate of the same probability, from a bigger sample than the stage before it.

  4. Work out the difference at each stage

    0.2,0.09,0.028,0.0020.2, \quad 0.09, \quad 0.028, \quad 0.002

    Each difference is relative frequency0.5|\text{relative frequency} - 0.5|, taken as a positive amount.

  5. Compare the differences

    0.2>0.09>0.028>0.0020.2 > 0.09 > 0.028 > 0.002

    In these results the difference gets smaller at every stage. The estimate is converging on the theoretical probability as the sample grows.

  6. Plot the relative frequency against the size of the sample

    (20,0.7),(200,0.59),(1000,0.528),(5000,0.502)(20, 0.7), \quad (200, 0.59), \quad (1000, 0.528), \quad (5000, 0.502)

    The graph shows exactly what the numbers show: wild swings from the smallest sample, then a settling towards the dashed theoretical line.

  7. Check the last estimate against the theory

    0.5020.5=0.002|0.502 - 0.5| = 0.002

    Even after 50005000 throws the relative frequency is 0.0020.002 away from 0.50.5 - close, but not equal.

  8. Rule out the claim that the last estimate is exactly the theory

    0.5020.50.502 \ne 0.5

    The two numbers are different, so any statement that they are equal is false on the arithmetic alone - and even if they had matched, that would not PROVE the object is fair.

  9. Rule out the claim that the results show bias

    gaps shrinkingbias\text{gaps shrinking} \ne \text{bias}

    The differences are getting smaller, not bigger, so the results are behaving exactly as a fair coin should. There is no evidence of bias here.

  10. State the answer

    The gaps shrink as the sample grows\text{The gaps shrink as the sample grows}

    The statement best supported by these results is: As the sample grows the relative frequency of heads gets closer to the theoretical probability 0.50.5 at every stage of this table: the differences are 0.20.2, 0.090.09, 0.0280.028 and 0.0020.002.

Answer
The gaps shrink as the sample grows\text{The gaps shrink as the sample grows}
Question 5
5 markschallenging
A fair spinner has 88 equal sections. 11 of the sections is red. The spinner is spun by two students. Sami spins it 4040 times and it lands on red 77 times. Tess spins it 800800 times and it lands on red 8484 times. Which statement about these two estimates is correct?
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Worked solution

  1. Work out the theoretical probability from the equally likely outcomes

    P(red)=18P(\text{red}) = \frac{1}{8}

    Because the spinner has 88 equal sections, so all 88 outcomes are equally likely, and 11 of them is red, the theoretical probability of red is 18=0.125\frac{1}{8} = 0.125. Both students are estimating this same value.

  2. Work out Sami's relative frequency

    740=0.175\frac{7}{40} = 0.175

    Sami got red 77 times in 4040 spins, so their estimate of the probability is 0.1750.175.

  3. Work out Tess's relative frequency

    84800=0.105\frac{84}{800} = 0.105

    Tess got red 8484 times in 800800 spins, so their estimate is 0.1050.105.

  4. Work out how far Sami's estimate is from the theory

    0.1750.125=0.05|0.175 - 0.125| = 0.05

    Sami's estimate is 0.050.05 away from the theoretical probability. The difference is taken as a positive amount.

  5. Work out how far Tess's estimate is from the theory

    0.1050.125=0.02|0.105 - 0.125| = 0.02

    Tess's estimate is 0.020.02 away from the theoretical probability.

  6. Compare the two differences

    0.02<0.050.02 < 0.05

    0.020.02 is smaller than 0.050.05, so Tess's estimate is the one closer to the theoretical probability.

  7. Put both estimates on the probability scale with the theory

    0.175,0.105,0.1250.175, \quad 0.105, \quad 0.125

    Marking all three values on the same scale shows which estimate has landed nearer the theoretical probability.

  8. Plot the two estimates against the size of the sample

    (40,0.175),(800,0.105)(40, 0.175), \quad (800, 0.105)

    The dashed line is the theoretical probability. The picture shows the same thing the arithmetic does: which estimate has landed nearer the line.

  9. Say which sample was the larger

    800>40800 > 40

    Tess used 800800 spins, more than the other student. A larger sample gives a more reliable estimate ON AVERAGE - it is the one to bet on before the results are seen.

  10. Say why the larger sample is not guaranteed to win

    tendency, not a guarantee\text{tendency}, \ \text{not a guarantee}

    This is the key point. A larger sample TENDS to be closer, but any single small sample can happen to land very close to the theoretical probability by luck. Only the actual differences can decide which of these two is closer, and that is why they were worked out. Here the larger sample (Tess's 800800 spins) has landed closer, as usually happens - but that was not guaranteed in advance.

  11. Rule out the idea that the estimates are equally close

    0.050.020.05 \ne 0.02

    The two differences are not equal, so the two estimates are not the same distance from the theoretical probability.

  12. Rule out the idea that the theory has to wait for the results

    theory first, experiment after\text{theory first}, \ \text{experiment after}

    The theoretical probability 18\frac{1}{8} was worked out from the equally likely outcomes before anything was thrown or spun. It does not need the experiment, and the experiment cannot change it.

  13. Say what neither estimate proves

    relative frequencyproof\text{relative frequency} \ne \text{proof}

    Neither student has proved anything about the probability. Each has made an estimate of it, and one of those estimates happens to be nearer the true value than the other.

  14. Say how either student could do better

    more trialsbetter estimate\text{more trials} \Rightarrow \text{better estimate}

    The only reliable way to improve an estimate is to carry out more trials, or to pool the two sets of results into one larger sample.

  15. State the answer

    Tess\text{Tess}

    Tess's estimate is closer: Tess's relative frequency 0.1050.105 differs from the theoretical probability 0.1250.125 by 0.020.02, and Sami's differs by 0.050.05, so Tess's estimate is closer.

Answer
Tess\text{Tess}

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