Recall that the probabilities of all the outcomes add up to 1
∑P(outcome)=1 The spinner lands on exactly one of the four numbers every time, so the four probabilities must add up to exactly 1.
Write the given probabilities over a common denominator
81+82+82 The lowest common denominator of the three given fractions is 8, so rewrite each of them in that denominator before adding.
Add the given probabilities
81+41+41=85=85 The three given probabilities come to 85.
Subtract from 1 to find the missing probability
P(4)=1−85=83 Everything left over belongs to 4: 1−85=83.
Check the four probabilities add to 1
81+41+41+83=1 Adding the answer back on gives exactly 1, which confirms it.
Check the missing probability is on the 0 to 1 scale
0≤83≤1 83 lies between 0 (impossible) and 1 (certain), so it is a possible probability.
Write the missing probability as a decimal
83=0.375 As a decimal the probability is 0.375, which makes it easy to place on the probability scale and easy to multiply.
Write down the rule for the expected number of successes
expected number=P(event)×number of trials Over many trials, an event with probability p happens about p of the time, so the expected number is the probability times the number of trials.
Substitute the probability and the number of spins
83×320 The probability is 83 and the spinner is spun 320 times.
Work out the expected number
83×320=120 320÷8×3=120.
Check the expected number is sensible
0≤120≤320 The spinner cannot land on 4 more than 320 times, and 120 is well inside that range.
Say what kind of answer this is
estimate, not a guarantee This is an ESTIMATE. In a real set of 320 spins the actual count would usually be near 120 but not exactly 120.
Link the estimate back to relative frequency
relative frequency→P(event) If the spinner really were spun 320 times, the relative frequency of 4 would be close to 83 - and closer still if it were spun more times. That is exactly how relative frequency estimates probability.
Note the mistake to avoid
41=83 in general Assuming each of the four numbers has probability 41 would only be right for a FAIR spinner. This spinner is biased, so the probabilities have to be read from the question.
State the answer
An estimate for the number of times the spinner lands on 4 is 120.