GCSE Priority of operations Practice Questions

Free GCSE Priority of operations practice questions with full step-by-step worked solutions. Covers order of operations, multiply before add, brackets first, division. Practise exam-style problems and check your method.

order of operationsmultiply before addbrackets firstdivisionpowers before addpowers
GCSE Foundation70 questionsStep-by-step solutions
Question 1
1 markeasy
Work out 3+4×23 + 4 \times 2.
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Worked solution

  1. Multiply before adding

    × before +\times\ \text{before}\ +

    BIDMAS says multiplication comes before addition, so do the 4×24\times 2 first.

  2. Do the multiplication

    4×2=84\times2=8

    4×2=84 \times 2 = 8.

  3. Now add

    3+8=113+8=11

    Add the 33 to get 1111.

Answer
1111
Question 2
1 markeasy
Work out 3×223 \times 2^2.
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Worked solution

  1. Power before multiplying

    22 first2^2\ \text{first}

    Indices come before multiplication, so square the 22 first.

  2. Work out the power

    22=42^2=4

    22=42^{2} = 4.

  3. Multiply

    3×4=123\times4=12

    3×4=123 \times 4 = 12.

Answer
1212
Question 3
2 marksintermediate
Use inverse operations to solve 3x=213x = 21.
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Worked solution

  1. Read the equation

    3x=213x=21

    3x means 33 times xx.

  2. The inverse of times 33

    ×3  ÷3\times3\ \to\ \div3

    To undo '×3\times 3' we divide by 33.

  3. Do the same to both sides

    x=21÷3x=21\div3

    Divide both sides by 33.

  4. Work it out

    21÷3=721\div3=7

    21÷3=721 \div 3 = 7.

  5. So

    x=7x=7

    The value of xx is 77.

  6. Check

    3×7=21 3\times7=21\ \checkmark

    Putting x=7x=7 back in gives 2121, which matches.

Answer
x=7x=7
Question 4
3 markshard
Use inverse operations to solve 2(x+5)=262(x + 5) = 26.
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Worked solution

  1. See what is done to xx

    2(x+5)=262(x+5)=26

    First 55 is added to xx, then the bracket is multiplied by 22.

  2. Undo in reverse order

    undo ×2 first\text{undo}\ \times2\ \text{first}

    Reverse the last operation first: undo the ×2\times 2.

  3. Divide both sides by 22

    x+5=26÷2x+5=26\div2

    The inverse of ×2\times 2 is ÷2\div 2.

  4. Work it out

    x+5=13x+5=13

    26÷2=1326 \div 2 = 13.

  5. Now undo the +5+5

    5 from both sides-5\ \text{from both sides}

    The inverse of +5+5 is 5-5.

  6. Subtract 55

    x=135x=13-5

    Subtract 55 from both sides.

  7. So

    x=8x=8

    135=813 - 5 = 8.

  8. Check: add 55

    8+5=138+5=13

    Put x=8x=8 back: 8+5=138+5 = 13.

  9. Check: times 22

    2×13=26 2\times13=26\ \checkmark

    2×13=262 \times 13 = 26, which matches.

  10. State the answer

    x=8x=8

    So x=8x = 8.

Answer
x=8x=8
Question 5
5 markschallenging
A student writes 4+6÷2=54 + 6 \div 2 = 5. Identify the mistake they made and give the correct answer.
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Worked solution

  1. Look at the answer given

    4+6÷2=5?4+6\div2=5?

    The student claims the answer is 55. Let us see where 55 could come from.

  2. Where 55 comes from

    (4+6)÷2(4+6)\div2

    55 is what you get if you add first: (4+6)÷2(4+6)\div 2.

  3. Check that

    (4+6)÷2=10÷2=5(4+6)\div2=10\div2=5

    10÷2=510 \div 2 = 5, so the student added before dividing.

  4. But there are no brackets

    4+6÷24+6\div2

    The original has no brackets, so we cannot add first.

  5. Recall the rule

    ÷ before +\div\ \text{before}\ +

    BIDMAS says division comes before addition.

  6. Do the division first

    6÷26\div2

    So work out 6÷26\div 2 first.

  7. Evaluate it

    6÷2=36\div2=3

    6÷2=36 \div 2 = 3.

  8. Now add

    4+34+3

    Add the 44 to the result.

  9. Evaluate

    4+3=74+3=7

    4+3=74+3 = 7.

  10. So the correct answer is

    4+6÷2=74+6\div2=7

    The right answer is 77, not 55.

  11. State the mistake

    added before dividing\text{added before dividing}

    The student's error was doing the addition before the division.

  12. What would justify their working

    (4+6)÷2(4+6)\div2

    Only brackets around 4+64+6 would make adding first correct.

  13. But those brackets are not there

    no brackets given\text{no brackets given}

    Without brackets, division must come first.

  14. Confirm the correct value

    6÷2=3, 4+3=76\div2=3,\ 4+3=7

    Dividing first then adding gives 77.

  15. State the answer

    correct answer=7\text{correct answer}=7

    So the mistake was adding before dividing, and the correct answer is 77.

Answer
error: added before dividing; correct answer =7\text{error: added before dividing; correct answer }=7

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