GCSE Similarity Practice Questions

Free GCSE Similarity practice questions with full step-by-step worked solutions. Covers similar triangles, scale factor, exact fraction, reduction. Practise exam-style problems and check your method.

similar trianglesscale factorexact fractionreductionreverse scale factormissing length
GCSE Foundation70 questionsStep-by-step solutions
Question 1
1 markeasy
Triangle ABCABC is similar to triangle PQRPQR, with AA corresponding to PP, BB to QQ and CC to RR. AB=4AB = 4 cm and PQ=12PQ = 12 cm. Work out the scale factor of the enlargement from triangle ABCABC to triangle PQRPQR.
Show worked solution

Worked solution

  1. Write the scale factor as a fraction

    k=PQAB=124k = \frac{PQ}{AB} = \frac{12}{4}

    Divide the new length by the old length — new over old, in that order.

  2. Simplify the fraction

    k=3k = 3

    Cancelling gives the exact scale factor 33. Leave it as a fraction rather than a rounded decimal.

  3. State the scale factor of the enlargement

    ABCPQR:k=3ABC \rightarrow PQR: \quad k = 3

    So the scale factor from triangle ABCABC to triangle PQRPQR is 33.

Answer
k=3k = 3
Question 2
2 markseasy
Triangle ABCABC is similar to triangle PQRPQR, with AA corresponding to PP, BB to QQ and CC to RR. AB=9AB = 9 cm, PQ=6PQ = 6 cm and QR=8QR = 8 cm. Which of these is the length of BCBC?
Show worked solution

Worked solution

  1. Work out the scale factor from triangle PQR to triangle ABC

    k=ABPQ=96=32k = \frac{AB}{PQ} = \frac{9}{6} = \frac{3}{2}

    Dividing the new length by the old one gives k=32k = \frac{3}{2}.

  2. Multiply the corresponding side by the scale factor

    BC=QR×k=8×32BC = QR \times k = 8 \times \frac{3}{2}

    BCBC corresponds to QRQR, so it is 32\frac{3}{2} times as long.

  3. Work out the missing length and choose that option

    BC=12 cmBC = 12 \text{ cm}

    So BC=12BC = 12 cm — that is the option to pick.

Answer
BC=12 cmBC = 12 \text{ cm}
Question 3
2 marksintermediate
In triangle ABCABC, DD lies on ABAB and EE lies on ACAC, and DEDE is parallel to BCBC. Angle ABC=48ABC = 48^\circ and angle ACB=67ACB = 67^\circ. Which statement is correct?
Show worked solution

Worked solution

  1. Name the two triangles that are similar

    ADEABC\triangle ADE \sim \triangle ABC

    The small triangle sits inside the large one and they share the angle at AA.

  2. Recall the corresponding angles fact

    DEBCDE \parallel BC

    A straight line crossing two parallel lines makes equal corresponding angles.

  3. Use the parallel line to match a pair of angles

    ADE=ABC,AED=ACB\angle ADE = \angle ABC, \quad \angle AED = \angle ACB

    The line ABAB crosses the two parallel lines DEDE and BCBC, so angle ADEADE and angle ABCABC are corresponding angles and are equal. The same argument on ACAC gives angle AEDAED = angle ACBACB.

  4. Write down the angles that gives you

    ADE=48,AED=67\angle ADE = 48^\circ, \quad \angle AED = 67^\circ

    So angle ADE=48ADE = 48^\circ and angle AED=67AED = 67^\circ.

  5. Rule out wrong option number 1

    AED=6748\angle AED = 67^\circ \ne 48^\circ

    Angle AEDAED is really 6767^\circ, not 4848^\circ, so this option is false.

  6. State the option you have chosen

    AED=67\angle AED = 67^\circ

    So angle AEDAED is 6767^\circ.

Answer
AED=67\angle AED = 67^\circ
Question 4
3 markshard
In triangle ABCABC, DD lies on ABAB and EE lies on ACAC, and DEDE is parallel to BCBC. Angle ABC=52ABC = 52^\circ and angle ACB=63ACB = 63^\circ. Which statement is correct?
Show worked solution

Worked solution

  1. Name the two triangles that are similar

    ADEABC\triangle ADE \sim \triangle ABC

    The small triangle sits inside the large one and they share the angle at AA.

  2. Recall the corresponding angles fact

    DEBCDE \parallel BC

    A straight line crossing two parallel lines makes equal corresponding angles.

  3. Work out the angle at A

    BAC=1805263=65\angle BAC = 180 - 52 - 63 = 65

    The angles of triangle ABCABC add to 180180^\circ, so the angle at AA is 6565^\circ. It belongs to both triangles.

  4. Note that the two triangles have the same three angles

    65,52,6365^\circ, \quad 52^\circ, \quad 63^\circ

    That is why they are similar: the shape is identical, only the size differs.

  5. Use the parallel line to match a pair of angles

    ADE=ABC,AED=ACB\angle ADE = \angle ABC, \quad \angle AED = \angle ACB

    The line ABAB crosses the two parallel lines DEDE and BCBC, so angle ADEADE and angle ABCABC are corresponding angles and are equal. The same argument on ACAC gives angle AEDAED = angle ACBACB.

  6. Write down the angles that gives you

    ADE=52,AED=63\angle ADE = 52^\circ, \quad \angle AED = 63^\circ

    So angle ADE=52ADE = 52^\circ and angle AED=63AED = 63^\circ.

  7. Rule out wrong option number 1

    AED=6352\angle AED = 63^\circ \ne 52^\circ

    Angle AEDAED is really 6363^\circ, not 5252^\circ, so this option is false.

  8. Rule out wrong option number 2

    AED=63117\angle AED = 63^\circ \ne 117^\circ

    Angle AEDAED is really 6363^\circ, not 117117^\circ, so this option is false.

  9. Rule out wrong option number 3

    ADE=5263\angle ADE = 52^\circ \ne 63^\circ

    Angle ADEADE is really 5252^\circ, not 6363^\circ, so this option is false.

  10. State the option you have chosen

    AED=63\angle AED = 63^\circ

    So angle AEDAED is 6363^\circ.

Answer
AED=63\angle AED = 63^\circ
Question 5
5 markschallenging
In triangles ABCABC and PQRPQR, angle BAC=55BAC = 55^\circ, angle ABC=60ABC = 60^\circ, angle QPR=55QPR = 55^\circ and angle PQR=70PQR = 70^\circ. No side lengths are given. Which of these statements about triangles ABCABC and PQRPQR is correct?
Show worked solution

Worked solution

  1. Recall the angle test for similar triangles

    AA\text{AA}

    If two pairs of corresponding angles are equal the triangles are similar. No side lengths are needed at all.

  2. Recall the angle sum of a triangle

    a+b+c=180a + b + c = 180^\circ

    This lets you fill in the third angle of each triangle before comparing them.

  3. Note what the question gives you

    four angles, no lengths\text{four angles, no lengths}

    Only angles are given, so any reason that talks about the ratio of sides cannot be used here.

  4. Plan the comparison

    complete both trianglescompare\text{complete both triangles} \rightarrow \text{compare}

    Work out the missing angle in each triangle, then compare the two sets of three.

  5. Note that the correspondence matters

    AP,BQ,CRA \leftrightarrow P, \quad B \leftrightarrow Q, \quad C \leftrightarrow R

    The letters pair the vertices, so compare angle BACBAC with angle QPRQPR, not with angle PQRPQR.

  6. Work out the third angle of triangle ABC

    ACB=1805560=65\angle ACB = 180 - 55 - 60 = 65

    The angles of a triangle add to 180180^\circ, so angle ACB=65ACB = 65^\circ.

  7. Work out the third angle of triangle PQR

    PRQ=1805570=55\angle PRQ = 180 - 55 - 70 = 55

    In the same way angle PRQ=55PRQ = 55^\circ.

  8. Compare the two sets of three angles

    {55,60,65}{55,70,55}\{55, 60, 65\} \ne \{55, 70, 55\}

    The two triangles do not have the same three angles, so they are not the same shape.

  9. State the correct conclusion

    ACB=6555=PRQ\angle ACB = 65 \ne 55 = \angle PRQ

    The third angles differ, so the triangles cannot be similar.

  10. Rule out the SSS reason

    no side lengths are given\text{no side lengths are given}

    SSS needs the three pairs of sides to be in the same ratio, but the question gives no side lengths at all, so this reason cannot be used.

  11. Rule out the SAS reason

    SAS needs side lengths too\text{SAS needs side lengths too}

    SAS needs two pairs of sides in the same ratio, and again there are no side lengths in the question, so this reason is not available either.

  12. Rule out the congruence claim

    equal anglesequal size\text{equal angles} \ne \text{equal size}

    Doubling every side of a triangle keeps all three angles the same but changes the triangle, so equal angles alone can never prove congruence.

  13. Rule out the remaining option

    BAC=55,QPR=55\angle BAC = 55, \quad \angle QPR = 55

    The claim that two pairs of angles are equal is false here: angle ABC=60ABC = 60^\circ but angle PQR=70PQR = 70^\circ.

  14. Note that similar shapes can be any size

    same anglessame shape\text{same angles} \Rightarrow \text{same shape}

    Similarity fixes the shape, not the size — that is the whole point of a scale factor.

  15. State the option you have chosen

    ABC≁PQR\triangle ABC \not\sim \triangle PQR

    So the triangles are not similar, because their third angles are 6565^\circ and 5555^\circ, which are different.

Answer
ABC≁PQR\triangle ABC \not\sim \triangle PQR

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