GCSE 3D solids, plans and elevations Practice Questions

Free GCSE 3D solids, plans and elevations practice questions with full step-by-step worked solutions. Covers faces, edges and vertices, properties of 3D solids, naming 3D solids, prisms. Practise exam-style problems and check your method.

faces, edges and verticesproperties of 3D solidsnaming 3D solidsprismspyramidsEuler formula
GCSE Foundation70 questionsStep-by-step solutions
Question 1
1 markeasy
Work out the number of faces of a cube.
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Worked solution

  1. Picture the solid and decide what its faces are.

    cube\text{cube}

    A face is a flat surface, an edge is where two faces meet and a vertex is a corner where edges meet. Counting them carefully beats guessing.

  2. Count the faces.

    faces=4+2=6\text{faces} = 4 + 2 = 6

    A prism has one face for each side of its cross-section, so 44 rectangles round the outside, plus the two 44-sided ends: 66 faces.

  3. State the number of faces.

    faces=6\text{faces} = 6

    The solid has 66 faces.

Answer
faces=6\text{faces} = 6
Question 2
2 markseasy
Which of these solids has exactly 99 edges?
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Worked solution

  1. Write down the rules for the edges of a prism and of a pyramid.

    Eprism=3n,Epyramid=2nE_{\text{prism}} = 3n, \quad E_{\text{pyramid}} = 2n

    A prism with an nn-sided cross-section has nn edges at each end and nn joining them, so 3n3n in all. A pyramid on an nn-sided base has nn base edges and nn sloping edges, so 2n2n.

  2. Apply the rule to each solid in the list.

    3×3=93 \times 3 = 9

    A triangular prism has 99 edges, which is what the question asks for.

  3. Name the solid.

    triangular prism\text{triangular prism}

    A triangular prism has exactly 99 edges.

Answer
a triangular prism\text{a triangular prism}
Question 3
2 marksintermediate
Which of these could be the numbers of faces, edges and vertices of a convex polyhedron?
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Worked solution

  1. Write down Euler's formula.

    FE+V=2F - E + V = 2

    For every convex polyhedron, faces minus edges plus vertices comes to 22. Any triple that fails this cannot be a solid.

  2. Test the triple that works.

    612+8=26 - 12 + 8 = 2

    With F=6F = 6, E=12E = 12 and V=8V = 8, Euler's formula gives 22, so this triple is possible.

  3. Test F equals 6, E equals 12 and V equals 9.

    612+9=326 - 12 + 9 = 3 \ne 2

    This gives 33, not 22, so no convex polyhedron has these numbers.

  4. Test F equals 5, E equals 9 and V equals 5.

    59+5=125 - 9 + 5 = 1 \ne 2

    This gives 11, not 22, so no convex polyhedron has these numbers.

  5. Test F equals 7, E equals 12 and V equals 8.

    712+8=327 - 12 + 8 = 3 \ne 2

    This gives 33, not 22, so no convex polyhedron has these numbers.

  6. State the possible triple.

    F=6,E=12,V=8F = 6, \quad E = 12, \quad V = 8

    Only 66 faces, 1212 edges and 88 vertices satisfies Euler's formula.

Answer
faces 6, edges 12, vertices 8\text{faces } 6, \text{ edges } 12, \text{ vertices } 8
Question 4
3 markshard
A solid is made from centimetre cubes standing on a flat table. Its base is 44 squares wide and 22 squares deep. The numbers of cubes in the stacks, read from left to right, are 2,1,3,12, 1, 3, 1 (front row) and 1,2,2,11, 2, 2, 1 (back row). Which list gives the heights, in cubes, of the columns of the front elevation of the solid, from left to right?
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Worked solution

  1. Say what you see when you look at the solid from the front.

    front elevation=the view from the front\text{front elevation} = \text{the view from the front}

    Looking from the front you look along the rows, so a stack is hidden behind any taller stack in the same column of the base.

  2. Work out the height of each column of the front elevation.

    front elevation=2, 2, 3, 1\text{front elevation} = 2,\ 2,\ 3,\ 1

    Looking from the front, a column is as tall as the TALLEST stack behind it, so take the largest number in each column of the grid: 2,2,3,12, 2, 3, 1.

  3. Rule out reading the front row only.

    2,1,3,12,2,3,12, 1, 3, 1 \ne 2, 2, 3, 1

    The front row is 2,1,3,12, 1, 3, 1, but a taller stack behind it still shows in the elevation, so the front row is not the elevation.

  4. Rule out adding the stacks in each column.

    3,3,5,22,2,3,13 , 3 , 5 , 2 \ne 2, 2, 3, 1

    Adding the stacks in a column would count cubes that are hidden behind one another. An elevation is a view, not a total.

  5. Rule out reading the columns from the wrong end.

    1,3,2,22,2,3,11, 3, 2, 2 \ne 2, 2, 3, 1

    The question asks for the columns from left to right, which is the order the stack heights are given in.

  6. Write the stack heights out as a grid, row by row from the front.

    2,1,3,11,2,2,12, 1, 3, 1 \\ 1, 2, 2, 1

    The base is 44 squares wide and 22 squares deep, so there are 88 stacks in all (a stack of 00 means that square is empty).

  7. Check the tallest column.

    max=3\max = 3

    The tallest column of the elevation, 33, must equal the tallest stack in the solid, and it does.

  8. Check against the side elevation.

    side=3, 2\text{side} = 3,\ 2

    The side elevation reads 3,23, 2 and also reaches 33, so both views agree about the height of the solid.

  9. Check the number of columns.

    columns=4\text{columns} = 4

    The base is 44 squares wide, so the front elevation has exactly 44 columns.

  10. State the front elevation.

    front elevation=2, 2, 3, 1\text{front elevation} = 2,\ 2,\ 3,\ 1

    From left to right the columns are 2,2,3,12, 2, 3, 1.

Answer
front elevation columns: 2,2,3,1\text{front elevation columns: } 2, 2, 3, 1
Question 5
5 markschallenging
A solid is made from centimetre cubes standing on a flat table. Its base is 33 squares wide and 33 squares deep. The numbers of cubes in the stacks, read from left to right, are 1,2,31, 2, 3 (front row), 3,2,13, 2, 1 (middle row) and 2,1,22, 1, 2 (back row). Which list gives the heights, in cubes, of the columns of the side elevation of the solid, from the front of the solid to the back?
Show worked solution

Worked solution

  1. Say what you see when you look at the solid from the side.

    side elevation=the view from the side\text{side elevation} = \text{the view from the side}

    Looking from the side you look along the width of the solid, so each ROW of the base gives one column of the elevation.

  2. Work out the height of each column of the side elevation.

    side elevation=3, 3, 2\text{side elevation} = 3,\ 3,\ 2

    Looking from the side, a column is as tall as the tallest stack in that row of the base, so take the largest number in each row: 3,3,23, 3, 2.

  3. Write the stack heights out as a grid, row by row from the front.

    1,2,33,2,12,1,21, 2, 3 \\ 3, 2, 1 \\ 2, 1, 2

    The base is 33 squares wide and 33 squares deep, so there are 99 stacks in all (a stack of 00 means that square is empty).

  4. Rule out using the columns of the base.

    3, 2, 33, 3, 23,\ 2,\ 3 \ne 3,\ 3,\ 2

    Taking the largest number in each column of the grid gives the FRONT elevation, 3,2,33, 2, 3, not the side elevation.

  5. Rule out adding the cubes in each row.

    6, 6, 53, 3, 26,\ 6,\ 5 \ne 3,\ 3,\ 2

    Adding a row counts cubes hidden behind one another. Only the tallest stack in the row is seen.

  6. Rule out reading the rows from the back.

    2, 3, 33, 3, 22,\ 3,\ 3 \ne 3,\ 3,\ 2

    The question asks for the columns from the front of the solid to the back, so the front row must come first.

  7. Check the number of columns.

    columns=3\text{columns} = 3

    The base is 33 squares deep, so the side elevation has 33 columns — not 33, which is what the front elevation has.

  8. Check the tallest column.

    max=3=3\max = 3 = 3

    The tallest column of the side elevation must be the tallest stack of the solid, 33 cubes.

  9. Work out the area of the side elevation.

    3+3+2=83 + 3 + 2 = 8

    The elevation covers 88 squares, so it has an area of 8 cm28\text{ cm}^2.

  10. Count the base squares that have at least one cube on them.

    covered squares=9 out of 9\text{covered squares} = 9 \text{ out of } 9

    The plan is the view from directly above, so a base square appears in the plan exactly when a cube stands on it: 99 of the 99 squares are covered.

  11. Check that the elevation cannot show every cube.

    8178 \le 17

    The solid has 1717 cubes but the side elevation shows only 88 squares, because the cubes behind hide each other.

  12. Check the front elevation reaches the same height.

    3=33 = 3

    Both elevations are views of the same solid, so their tallest columns must agree.

  13. Add up the cubes in each row of the base.

    1+2+3=6,3+2+1=6,2+1+2=51 + 2 + 3 = 6 , \quad 3 + 2 + 1 = 6 , \quad 2 + 1 + 2 = 5

    Row by row from the front, the stacks hold 6,6and56, 6 and 5 cubes.

  14. Add the row totals to get the number of cubes.

    6+6+5=176 + 6 + 5 = 17

    Altogether the solid uses 1717 cubes.

  15. State the side elevation.

    side elevation=3, 3, 2\text{side elevation} = 3,\ 3,\ 2

    From the front to the back the columns are 3,3,23, 3, 2.

Answer
side elevation columns: 3,3,2\text{side elevation columns: } 3, 3, 2

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