GCSE Circles: circumference and area Practice Questions

Free GCSE Circles: circumference and area practice questions with full step-by-step worked solutions. Covers circumference of a circle, C = 2 pi r, answer in terms of pi, exact value. Practise exam-style problems and check your method.

circumference of a circleC = 2 pi ranswer in terms of piexact valuearea of a circleA = pi r squared
GCSE Foundation70 questionsStep-by-step solutions
Question 1
2 markseasy
A circle has radius 55 cm. Work out the circumference of the circle. Give your answer in terms of π\pi.
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Worked solution

  1. Write down the formula for the circumference of a circle.

    C=2πr=πdC = 2\pi r = \pi d

    The circumference is 2πr2\pi r, where rr is the radius. The diameter is d=2rd = 2r, so this is the same as πd\pi d.

  2. Substitute the radius into the formula.

    C=2×π×5C = 2 \times \pi \times 5

    The radius is 55, so C=2π×5C = 2\pi \times 5.

  3. State the circumference.

    C=10π cmC = 10\pi\text{ cm}

    The circumference is 10π cm10\pi\text{ cm}.

Answer
C=10π cmC = 10\pi\text{ cm}
Question 2
2 markseasy
Which of these expressions gives the area of a circle of radius rr?
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Worked solution

  1. Recall the area formula.

    A=πr2A = \pi r^2

    The area of a circle of radius rr is πr2\pi r^2: the radius is squared and the result is multiplied by π\pi.

  2. Rule out the expressions that are not areas.

    2πr and πr are lengths2\pi r \text{ and } \pi r \text{ are lengths}

    An area needs two lengths multiplied together, so 2πr2\pi r and πr\pi r are the wrong kind of quantity. (πr)2(\pi r)^2 squares π\pi as well as rr, which is about three times too big, and 2πr22\pi r^2 is exactly twice the area.

  3. Select the correct expression.

    A=πr2A = \pi r^2

    The area of a circle of radius rr is πr2\pi r^2.

Answer
A=πr2A = \pi r^2
Question 3
2 marksintermediate
Which of these expressions gives the area of a semicircle of radius rr?
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Worked solution

  1. Start from the area of the whole circle.

    A=πr2A = \pi r^2

    A circle of radius rr has area πr2\pi r^2.

  2. Halve it.

    A=12πr2A = \frac{1}{2}\pi r^2

    A semicircle is exactly half of the circle, so its area is half of πr2\pi r^2.

  3. Rule out the expression that is a length.

    12πr is a length\frac{1}{2}\pi r \text{ is a length}

    There is no r2r^2 in 12πr\frac{1}{2}\pi r, so it cannot be an area at all.

  4. Rule out the fractions that are the wrong size.

    14πr2 and 2πr2\frac{1}{4}\pi r^2 \text{ and } 2\pi r^2

    14πr2\frac{1}{4}\pi r^2 is a QUARTER circle and 2πr22\pi r^2 is twice the whole circle, so neither is a semicircle.

  5. Check the answer on a circle of radius 2.

    12π×22=2π\frac{1}{2}\pi \times 2^2 = 2\pi

    A semicircle of radius 22 has area 2π2\pi, which is half of the 4π4\pi of the whole circle, as it should be.

  6. Select the correct expression.

    A=12πr2A = \frac{1}{2}\pi r^2

    The area of a semicircle of radius rr is 12πr2\frac{1}{2}\pi r^2.

Answer
A=12πr2A = \frac{1}{2}\pi r^2
Question 4
3 markshard
A circle has radius 66 cm. Which statement is correct?
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Worked solution

  1. Write down the formula for the circumference of a circle.

    C=2πr=πdC = 2\pi r = \pi d

    The circumference is 2πr2\pi r, where rr is the radius. The diameter is d=2rd = 2r, so this is the same as πd\pi d.

  2. Work out the circumference.

    C=2π×6=12πC = 2\pi \times 6 = 12\pi

    The circumference is 12π12\pi.

  3. Write down the formula for the area of a circle.

    A=πr2A = \pi r^2

    The area of a circle of radius rr is πr2\pi r^2. Only the radius is squared — π\pi is not.

  4. Work out the area.

    A=π×62=36πA = \pi \times 6^2 = 36\pi

    The area is 36π36\pi.

  5. Rule out the option with the two answers swapped.

    123612 \ne 36

    Swapping the circumference and the area is the commonest slip here, and the units give it away: an area cannot be measured in centimetres.

  6. Rule out the option that forgets to double the radius.

    π×62π×6\pi \times 6 \ne 2\pi \times 6

    6π6\pi is only half the circumference.

  7. Rule out the option that uses the diameter in the area formula.

    π×122=144π36π\pi \times 12^2 = 144\pi \ne 36\pi

    Putting the diameter into A=πr2A = \pi r^2 gives 144π144\pi, four times too big.

  8. Check the units of each part.

    C in cm,A in cm2C \text{ in cm}, \quad A \text{ in cm}^2

    A circumference is a length and an area is a length squared, so only one option has both units right as well as both numbers right.

  9. Check the answers with decimals.

    12π37.69,36π113.0912\pi \approx 37.69, \quad 36\pi \approx 113.09

    The decimal values confirm that the area is much the bigger number here.

  10. Select the correct statement.

    C=12π,A=36πC = 12\pi, \quad A = 36\pi

    The circumference is 12π12\pi cm and the area is 36π36\pi cm2^2.

Answer
C=12π,A=36πC = 12\pi, \quad A = 36\pi
Question 5
5 markschallenging
The circumference of a circle is 26π26\pi cm. Which statement is correct?
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Worked solution

  1. Write down the formula for the circumference of a circle.

    C=2πr=πdC = 2\pi r = \pi d

    The circumference is 2πr2\pi r, where rr is the radius. The diameter is d=2rd = 2r, so this is the same as πd\pi d.

  2. Use the diameter form of the formula.

    πd=26π\pi d = 26\pi

    The circumference is given as a multiple of π\pi, so comparing it with πd\pi d is the quickest route.

  3. Divide both sides by pi.

    d=26d = 26

    The π\pi cancels straight away, leaving the diameter.

  4. Halve the diameter to get the radius.

    r=262=13r = \frac{26}{2} = 13

    The radius is 1313.

  5. Check with the other form of the formula.

    2π×13=26π2\pi \times 13 = 26\pi

    Putting r=13r = 13 into C=2πrC = 2\pi r gives back 26π26\pi, so the two values are consistent.

  6. Rule out the option with the two answers swapped.

    13<2613 < 26

    The radius is always the smaller of the two, so a radius bigger than the diameter is impossible.

  7. Rule out the option that doubles the circumference number.

    522652 \ne 26

    Dividing 26π26\pi by π\pi gives 2626, not 5252; that option has multiplied where it should have divided.

  8. Rule out the option with equal radius and diameter.

    d=2rdrd = 2r \Rightarrow d \ne r

    A diameter is twice the radius, so they can never be equal.

  9. Rule out the option that halves twice.

    132=6.513\frac{13}{2} = 6.5 \ne 13

    That option has halved 2626 twice over, once too often.

  10. Work out the area as a further check.

    A=π×132=169πA = \pi \times 13^2 = 169\pi

    With r=13r = 13 the area is 169π169\pi, a sensible size for a circle of circumference 26π26\pi.

  11. Check the decimal circumference.

    26π81.6826\pi \approx 81.68

    The circumference is about 81.6881.68 cm, a little more than three diameters, as it should be.

  12. Note the mistake to avoid.

    26π2π=1326\frac{26\pi}{2\pi} = 13 \ne 26

    Dividing by 2π2\pi gives the radius; dividing by π\pi gives the diameter. Mixing the two up is what every wrong option here does.

  13. Check the units.

    d and r are lengthsd \text{ and } r \text{ are lengths}

    Both answers are lengths in centimetres, which matches the units of the circumference.

  14. Check the diameter against the circumference.

    26π26=π\frac{26\pi}{26} = \pi

    The circumference divided by the diameter is π\pi for every circle, so this pair of values is consistent.

  15. Select the correct statement.

    d=26,r=13d = 26, \quad r = 13

    The diameter is 2626 cm and the radius is 1313 cm.

Answer
d=26,r=13d = 26, \quad r = 13

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