First-order differential equations Worked Solutions — Further Maths Maths

Fully worked, step-by-step solutions to Further Maths First-order differential equations questions. See exactly how to solve problems on integrating-factor, linear-first-order, separable, first-order.

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Further Maths70 questionsStep-by-step solutions
Question 1
2 markseasy
Find an integrating factor for the differential equation dydx+3y=e2x\frac{dy}{dx}+3y=\mathrm{e}^{2x}.

Worked solution

  1. Identify P(x)P\left(x\right) and Q(x)Q\left(x\right)

    P(x)=3,Q(x)=e2xP\left(x\right)=3,\qquad Q\left(x\right)=\mathrm{e}^{2x}

    PP is the coefficient of yy once the equation is in standard form.

  2. Form the integrating factor

    μ=e3dx=e3x\mu=\mathrm{e}^{\int 3\,dx}=\mathrm{e}^{3x}

    This is the multiplier that makes the left-hand side exact.

  3. State the integrating factor

    μ=e3x\mu=\mathrm{e}^{3x}

    Multiplying the equation by this factor would make the left-hand side an exact derivative.

Answer
μ=e3x\mu=\mathrm{e}^{3x}
Question 2
2 markseasy
Find an integrating factor for the differential equation dydx+2yx=x3\frac{dy}{dx}+\frac{2y}{x}=x^{3}.

Worked solution

  1. Identify P(x)P\left(x\right) and Q(x)Q\left(x\right)

    P(x)=2x,Q(x)=x3P\left(x\right)=\frac{2}{x},\qquad Q\left(x\right)=x^{3}

    PP is the coefficient of yy once the equation is in standard form.

  2. Integrate P(x)P\left(x\right)

    2xdx=2ln(x)\int \frac{2}{x}\,dx=2\ln{\left(x\right)}

    No constant of integration is needed at this stage.

  3. Form the integrating factor

    μ=e2xdx=e2ln(x)=x2\mu=\mathrm{e}^{\int \frac{2}{x}\,dx}=\mathrm{e}^{2\ln{\left(x\right)}}=x^{2}

    This is the multiplier that makes the left-hand side exact.

  4. State the integrating factor

    μ=x2\mu=x^{2}

    Multiplying the equation by this factor would make the left-hand side an exact derivative.

Answer
μ=x2\mu=x^{2}
Question 3
2 markseasy
Find an integrating factor for the differential equation dydx4y=5\frac{dy}{dx}-4y=5.

Worked solution

  1. Identify P(x)P\left(x\right) and Q(x)Q\left(x\right)

    P(x)=4,Q(x)=5P\left(x\right)=-4,\qquad Q\left(x\right)=5

    PP is the coefficient of yy once the equation is in standard form.

  2. Form the integrating factor

    μ=e4dx=e4x\mu=\mathrm{e}^{\int -4\,dx}=\mathrm{e}^{-4x}

    This is the multiplier that makes the left-hand side exact.

  3. State the integrating factor

    μ=e4x\mu=\mathrm{e}^{-4x}

    Multiplying the equation by this factor would make the left-hand side an exact derivative.

Answer
μ=e4x\mu=\mathrm{e}^{-4x}
Question 4
2 markseasy
Find an integrating factor for the differential equation dydx+ytan(x)=cos(x)\frac{dy}{dx}+y\tan{\left(x\right)}=\cos{\left(x\right)}.

Worked solution

  1. Identify P(x)P\left(x\right) and Q(x)Q\left(x\right)

    P(x)=tan(x),Q(x)=cos(x)P\left(x\right)=\tan{\left(x\right)},\qquad Q\left(x\right)=\cos{\left(x\right)}

    PP is the coefficient of yy once the equation is in standard form.

  2. Integrate P(x)P\left(x\right)

    tan(x)dx=ln(cos(x))\int \tan{\left(x\right)}\,dx=-\ln{\left(\cos{\left(x\right)}\right)}

    No constant of integration is needed at this stage.

  3. Form the integrating factor

    μ=etan(x)dx=eln(cos(x))=sec(x)\mu=\mathrm{e}^{\int \tan{\left(x\right)}\,dx}=\mathrm{e}^{-\ln{\left(\cos{\left(x\right)}\right)}}=\sec{\left(x\right)}

    This is the multiplier that makes the left-hand side exact.

  4. State the integrating factor

    μ=sec(x)\mu=\sec{\left(x\right)}

    Multiplying the equation by this factor would make the left-hand side an exact derivative.

Answer
μ=sec(x)\mu=\sec{\left(x\right)}
Question 5
2 markseasy
Find an integrating factor for the differential equation dydx+5yx=1x\frac{dy}{dx}+\frac{5y}{x}=\frac{1}{x}.

Worked solution

  1. Identify P(x)P\left(x\right) and Q(x)Q\left(x\right)

    P(x)=5x,Q(x)=1xP\left(x\right)=\frac{5}{x},\qquad Q\left(x\right)=\frac{1}{x}

    PP is the coefficient of yy once the equation is in standard form.

  2. Form the integrating factor

    μ=e5xdx=e5ln(x)=x5\mu=\mathrm{e}^{\int \frac{5}{x}\,dx}=\mathrm{e}^{5\ln{\left(x\right)}}=x^{5}

    This is the multiplier that makes the left-hand side exact.

  3. State the integrating factor

    μ=x5\mu=x^{5}

    Multiplying the equation by this factor would make the left-hand side an exact derivative.

Answer
μ=x5\mu=x^{5}

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