Challenging, exam-style Further Maths Argand diagrams questions with worked solutions. Stretch yourself on the hardest argand, modulus, products, quotients problems.
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Further Maths34 questionsStep-by-step solutions
Question 1
8 markschallenging
In which quadrant of the Argand diagram does the point representing z=4−9i lie?
Show worked solution
Worked solution
Read off the coordinates
z⟶(4,−9)
The real part is the x-coordinate and the imaginary part the y-coordinate.
Use the signs of the coordinates
x>0,y<0
The pair of signs identifies the quadrant.
Recall the quadrant convention
I:x>0,y>0;II:x<0,y>0;III:x<0,y<0;IV:x>0,y<0
Quadrants are numbered anticlockwise from the positive real axis.
Confirm with the argument
argz=−atan(49)
The argument also confirms the quadrant.
Recall the modulus formula
∣z∣=x2+y2
The modulus is the distance of the point from the origin on the Argand diagram.
Recall how the argument is measured
argz=angle from the positive real axis, measured anticlockwise
The argument is the angle the vector from the origin makes with the positive real axis.
Plot the number as a point
z=x+iy⟶(x,y)
A complex number is represented by the point (x,y) on the Argand diagram.
Identify the quadrant from the signs
signs of x and y fix the quadrant
The quadrant tells you how to adjust the acute angle to get the argument.
Recall modulus-argument form
z=r(cosθ+isinθ)
Here r=∣z∣ and θ=argz.
Recall the multiplication rule for moduli
∣z1z2∣=∣z1∣∣z2∣
Moduli multiply when complex numbers are multiplied.
Recall the addition rule for arguments
arg(z1z2)=argz1+argz2
Arguments add when complex numbers are multiplied.
Recall the division rule for moduli
z2z1=∣z2∣∣z1∣
Moduli divide when complex numbers are divided.
Interpret ∣z−a∣ as a distance
∣z−a∣=distance from z to a
This geometric reading is the key to every locus question.
Recall the circle locus
∣z−a∣=ris a circle, centre a, radius r
All points a fixed distance from a fixed point form a circle.
Select the quadrant
quadrant IV
This is where the point lies.
Answer
The fourth quadrant
Question 2
8 markschallenging
Which of the following best describes the locus of points z on an Argand diagram satisfying arg(z−(2−i))=32π?
Show worked solution
Worked solution
Interpret the argument condition
arg(z−(2−i))=32π
The vector from the fixed point to z has a fixed direction.
Recall the half-line locus
half-line from (2,−1) at angle 32π
Only one direction is allowed, so the locus is a half-line, not a full line.
Note the endpoint is excluded
z=2−i
At the endpoint the argument is undefined.
Reject the opposite direction
arg(z−(2−i))=−3π
The opposite ray corresponds to a different argument.
Recall the modulus formula
∣z∣=x2+y2
The modulus is the distance of the point from the origin on the Argand diagram.
Recall how the argument is measured
argz=angle from the positive real axis, measured anticlockwise
The argument is the angle the vector from the origin makes with the positive real axis.
Plot the number as a point
z=x+iy⟶(x,y)
A complex number is represented by the point (x,y) on the Argand diagram.
Identify the quadrant from the signs
signs of x and y fix the quadrant
The quadrant tells you how to adjust the acute angle to get the argument.
Recall modulus-argument form
z=r(cosθ+isinθ)
Here r=∣z∣ and θ=argz.
Recall the multiplication rule for moduli
∣z1z2∣=∣z1∣∣z2∣
Moduli multiply when complex numbers are multiplied.
Recall the addition rule for arguments
arg(z1z2)=argz1+argz2
Arguments add when complex numbers are multiplied.
Recall the division rule for moduli
z2z1=∣z2∣∣z1∣
Moduli divide when complex numbers are divided.
Interpret ∣z−a∣ as a distance
∣z−a∣=distance from z to a
This geometric reading is the key to every locus question.
Recall the circle locus
∣z−a∣=ris a circle, centre a, radius r
All points a fixed distance from a fixed point form a circle.
Select the correct description
half-line from (2,−1) at angle 32π to the real axis
This matches the locus exactly.
Answer
A half-line starting at (2,−1) making an angle of 32π with the positive real axis
Question 3
8 markschallenging
Which of the following best describes the locus of points z on an Argand diagram satisfying ∣z−(−1+4i)∣=∣z−(5−2i)∣?
Show worked solution
Worked solution
Interpret each modulus as a distance
∣z−(−1+4i)∣=∣z−(5−2i)∣
z is equidistant from the two fixed points.
Recall the equidistant locus
perpendicular bisector of AB
The set of points equidistant from A and B is the perpendicular bisector of AB.
Name the two fixed points
A(−1,4),B(5,−2)
These are the points represented by the two complex numbers.
Give the Cartesian equation as a check
y=x−1
The locus is a straight line, not a circle.
Recall the modulus formula
∣z∣=x2+y2
The modulus is the distance of the point from the origin on the Argand diagram.
Recall how the argument is measured
argz=angle from the positive real axis, measured anticlockwise
The argument is the angle the vector from the origin makes with the positive real axis.
Plot the number as a point
z=x+iy⟶(x,y)
A complex number is represented by the point (x,y) on the Argand diagram.
Identify the quadrant from the signs
signs of x and y fix the quadrant
The quadrant tells you how to adjust the acute angle to get the argument.
Recall modulus-argument form
z=r(cosθ+isinθ)
Here r=∣z∣ and θ=argz.
Recall the multiplication rule for moduli
∣z1z2∣=∣z1∣∣z2∣
Moduli multiply when complex numbers are multiplied.
Recall the addition rule for arguments
arg(z1z2)=argz1+argz2
Arguments add when complex numbers are multiplied.
Recall the division rule for moduli
z2z1=∣z2∣∣z1∣
Moduli divide when complex numbers are divided.
Interpret ∣z−a∣ as a distance
∣z−a∣=distance from z to a
This geometric reading is the key to every locus question.
Recall the circle locus
∣z−a∣=ris a circle, centre a, radius r
All points a fixed distance from a fixed point form a circle.
Select the correct description
perpendicular bisector of the segment AB
This matches the locus exactly.
Answer
The perpendicular bisector of the line segment joining (−1,4) and (5,−2)
Question 4
8 markschallenging
Which of the following is the argument of z=−5−5i, in the interval −π<θ≤π?
Show worked solution
Worked solution
Locate the point on the Argand diagram
z⟶(−5,−5)
The quadrant determines the sign and size of the argument.
Measure the angle from the positive real axis
argz=−43π
Anticlockwise is positive, clockwise is negative.
Reject the reflected angle
−argz=43π
This would be the argument of the conjugate.
Confirm the principal range
−π<−43π≤π
The principal argument lies in this interval.
Recall the modulus formula
∣z∣=x2+y2
The modulus is the distance of the point from the origin on the Argand diagram.
Recall how the argument is measured
argz=angle from the positive real axis, measured anticlockwise
The argument is the angle the vector from the origin makes with the positive real axis.
Plot the number as a point
z=x+iy⟶(x,y)
A complex number is represented by the point (x,y) on the Argand diagram.
Identify the quadrant from the signs
signs of x and y fix the quadrant
The quadrant tells you how to adjust the acute angle to get the argument.
Recall modulus-argument form
z=r(cosθ+isinθ)
Here r=∣z∣ and θ=argz.
Recall the multiplication rule for moduli
∣z1z2∣=∣z1∣∣z2∣
Moduli multiply when complex numbers are multiplied.
Recall the addition rule for arguments
arg(z1z2)=argz1+argz2
Arguments add when complex numbers are multiplied.
Recall the division rule for moduli
z2z1=∣z2∣∣z1∣
Moduli divide when complex numbers are divided.
Interpret ∣z−a∣ as a distance
∣z−a∣=distance from z to a
This geometric reading is the key to every locus question.
Recall the circle locus
∣z−a∣=ris a circle, centre a, radius r
All points a fixed distance from a fixed point form a circle.
Select the matching option
argz=−43π
This option equals the computed argument.
Answer
−43π
Question 5
8 markschallenging
Given z=−1+i, find the exact value of z6.
Show worked solution
Worked solution
Find the modulus of z
∣z∣=2
Apply x2+y2 to z.
Use ∣zn∣=∣z∣n
z6=(2)6=8
The modulus of a power is the power of the modulus.
Justify the rule from the product rule
z6=6∣z∣⋯∣z∣
Repeated use of ∣z1z2∣=∣z1∣∣z2∣.
Raise the modulus to the power
(2)6=8
Evaluate the power exactly.
Note the argument plays no part
z6depends only on ∣z∣
Only the modulus is required here.
Simplify to exact form
z6=8
Leave surds in exact form.
Recall the modulus formula
∣z∣=x2+y2
The modulus is the distance of the point from the origin on the Argand diagram.
Recall how the argument is measured
argz=angle from the positive real axis, measured anticlockwise
The argument is the angle the vector from the origin makes with the positive real axis.
Plot the number as a point
z=x+iy⟶(x,y)
A complex number is represented by the point (x,y) on the Argand diagram.
Identify the quadrant from the signs
signs of x and y fix the quadrant
The quadrant tells you how to adjust the acute angle to get the argument.
Recall modulus-argument form
z=r(cosθ+isinθ)
Here r=∣z∣ and θ=argz.
Recall the multiplication rule for moduli
∣z1z2∣=∣z1∣∣z2∣
Moduli multiply when complex numbers are multiplied.
Recall the addition rule for arguments
arg(z1z2)=argz1+argz2
Arguments add when complex numbers are multiplied.
Recall the division rule for moduli
z2z1=∣z2∣∣z1∣
Moduli divide when complex numbers are divided.
State the exact value
z6=8
This is the modulus of the required power.
Answer
8
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