Hard GCSE Simple and compound interest Questions

Challenging, exam-style GCSE Simple and compound interest questions with worked solutions. Stretch yourself on the hardest compound interest, year by year, rounding to the penny, interest earned problems.

compound interestyear by yearrounding to the pennyinterest earneddepreciationcompound decay
GCSE Foundation34 questionsStep-by-step solutions
Question 1
6 markschallenging
Jonah opens an account with £500\pounds 500. The account pays 6%6\% compound interest per year. At the end of each year, immediately after the interest has been added, Jonah pays in a further £500\pounds 500. Work out how much is in the account at the end of 55 years.
Show worked solution

Worked solution

  1. Plan the year-by-year table

    balance×1.06+500\text{balance} \to \times 1.06 \to +\,500

    Interest first, then the £500\pounds 500 payment, five times over. The exact balance carries forward every year. Exam convention: keep the full unrounded balance in the calculator all the way through and round to the nearest penny only at the very end.

  2. Write the yearly percentage as a multiplier

    100%+6%=106%=1.06100\% + 6\% = 106\% = 1.06

    A 6%6\% increase keeps the whole 100%100\% and adds 6%6\% on top, so multiply by 1.061.06 each year.

  3. Year 11: add the interest

    £500×1.06=£530\pounds 500 \times 1.06 = \pounds 530

    6%6\% interest on £500\pounds 500 is £30.00\pounds 30.00, giving £530\pounds 530.

  4. Year 11: add the £500\pounds 500 payment

    £530+500=£1030\pounds 530 + 500 = \pounds 1030

    The payment goes in after the interest, so the balance is £1030\pounds 1030.

  5. Year 22: add the interest

    £1030×1.06=£1091.80\pounds 1030 \times 1.06 = \pounds 1091.80

    6%6\% interest on £1030\pounds 1030 is £61.80\pounds 61.80, giving £1091.80\pounds 1091.80.

  6. Year 22: add the £500\pounds 500 payment

    £1091.80+500=£1591.80\pounds 1091.80 + 500 = \pounds 1591.80

    The payment goes in after the interest, so the balance is £1591.80\pounds 1591.80.

  7. Year 33: add the interest

    £1591.80×1.06£1687.31\pounds 1591.80 \times 1.06 \approx \pounds 1687.31

    6%6\% interest on £1591.80\pounds 1591.80 is £95.51\pounds 95.51, giving £1687.31\pounds 1687.31.

  8. Year 33: add the £500\pounds 500 payment

    £1687.31+500£2187.31\pounds 1687.31 + 500 \approx \pounds 2187.31

    The payment goes in after the interest, so the balance is £2187.31\pounds 2187.31.

  9. Year 44: add the interest

    £2187.31×1.06£2318.55\pounds 2187.31 \times 1.06 \approx \pounds 2318.55

    6%6\% interest on £2187.31\pounds 2187.31 is £131.24\pounds 131.24, giving £2318.55\pounds 2318.55.

  10. Year 44: add the £500\pounds 500 payment

    £2318.55+500£2818.55\pounds 2318.55 + 500 \approx \pounds 2818.55

    The payment goes in after the interest, so the balance is £2818.55\pounds 2818.55.

  11. Year 55: add the interest

    £2818.55×1.06£2987.66\pounds 2818.55 \times 1.06 \approx \pounds 2987.66

    6%6\% interest on £2818.55\pounds 2818.55 is £169.11\pounds 169.11, giving £2987.66\pounds 2987.66.

  12. Year 55: add the £500\pounds 500 payment

    £2987.66+500£3487.66\pounds 2987.66 + 500 \approx \pounds 3487.66

    The payment goes in after the interest, so the balance is £3487.66\pounds 3487.66.

  13. Round to the nearest penny

    £3487.66£3487.66\pounds 3487.66 \to \pounds 3487.66

    The full-precision balance is rounded to the penny only at the end.

  14. Work out the total she paid in

    500+5×500=£3000500 + 5 \times 500 = \pounds 3000

    She paid in £3000\pounds 3000 of her own money altogether.

  15. State the answer

    £3487.66\pounds 3487.66

    After 55 years the account holds £3487.66\pounds 3487.66, of which £487.66\pounds 487.66 is interest.

Answer
£3487.66\pounds 3487.66
Question 2
6 markschallenging
Ellie pays £2500\pounds 2500 into an account that gives 3.5%3.5\% compound interest per year. At the end of every year, immediately after the interest has been added, she pays in a further £100\pounds 100. Work out the smallest number of complete years before the account is worth more than £3200\pounds 3200.
Show worked solution

Worked solution

  1. Plan the year-by-year table

    balance×1.035+100\text{balance} \to \times 1.035 \to +\,100

    Each year: interest first, then the £100\pounds 100 payment. Keep going until the balance passes £3200\pounds 3200. Exam convention: keep the full unrounded balance in the calculator all the way through and round to the nearest penny only at the very end.

  2. Write the yearly percentage as a multiplier

    100%+3.5%=103.5%=1.035100\% + 3.5\% = 103.5\% = 1.035

    A 3.5%3.5\% increase keeps the whole 100%100\% and adds 3.5%3.5\% on top, so multiply by 1.0351.035 each year.

  3. Year 11: interest, then the payment

    £2500×1.035+100=£2587.50+100=£2687.50\pounds 2500 \times 1.035 + 100 = \pounds 2587.50 + 100 = \pounds 2687.50

    Interest of £87.50\pounds 87.50 is added to £2500\pounds 2500, then the £100\pounds 100 payment goes in: £2687.50\pounds 2687.50. The exact balance carries forward.

  4. Year 22: interest, then the payment

    £2687.50×1.035+100£2781.56+100£2881.56\pounds 2687.50 \times 1.035 + 100 \approx \pounds 2781.56 + 100 \approx \pounds 2881.56

    Interest of £94.06\pounds 94.06 is added to £2687.50\pounds 2687.50, then the £100\pounds 100 payment goes in: £2881.56\pounds 2881.56. The exact balance carries forward.

  5. Year 33: interest, then the payment

    £2881.56×1.035+100£2982.42+100£3082.42\pounds 2881.56 \times 1.035 + 100 \approx \pounds 2982.42 + 100 \approx \pounds 3082.42

    Interest of £100.85\pounds 100.85 is added to £2881.56\pounds 2881.56, then the £100\pounds 100 payment goes in: £3082.42\pounds 3082.42. The exact balance carries forward.

  6. Year 44: interest, then the payment

    £3082.42×1.035+100£3190.30+100£3290.30\pounds 3082.42 \times 1.035 + 100 \approx \pounds 3190.30 + 100 \approx \pounds 3290.30

    Interest of £107.88\pounds 107.88 is added to £3082.42\pounds 3082.42, then the £100\pounds 100 payment goes in: £3290.30\pounds 3290.30. The exact balance carries forward.

  7. Year 55: interest, then the payment

    £3290.30×1.035+100£3405.46+100£3505.46\pounds 3290.30 \times 1.035 + 100 \approx \pounds 3405.46 + 100 \approx \pounds 3505.46

    Interest of £115.16\pounds 115.16 is added to £3290.30\pounds 3290.30, then the £100\pounds 100 payment goes in: £3505.46\pounds 3505.46. The exact balance carries forward.

  8. Check year 33 against the target

    £3082.42<£3200\pounds 3082.42 < \pounds 3200

    After 33 years the balance is £3082.42\pounds 3082.42, which is still £117.58\pounds 117.58 SHORT of £3200\pounds 3200. So 33 years is not enough.

  9. Check year 44 against the target

    £3290.30>£3200\pounds 3290.30 > \pounds 3200

    After 44 years the balance is £3290.30\pounds 3290.30, which is £90.30\pounds 90.30 OVER £3200\pounds 3200. Year 44 is the first year the target is passed.

  10. Check the total she has paid in

    2500+4×100=£29002500 + 4 \times 100 = \pounds 2900

    She has paid in £2900\pounds 2900 of her own money, so £390.30\pounds 390.30 of the final balance is interest.

  11. Say why the payments alone are not enough

    2500+4×100=2900<32002500 + 4 \times 100 = 2900 < 3200

    Without any interest the account would hold only £2900\pounds 2900 after 44 years, which is under the target. The interest is doing real work here.

  12. Say why the interest alone is not enough either

    2500×1.0354£2868.81<£32002500 \times 1.035^{4} \approx \pounds 2868.81 < \pounds 3200

    And with no payments at all, £2500\pounds 2500 would grow to only £2868.81\pounds 2868.81 in 44 years. It takes BOTH the payments and the interest to pass £3200\pounds 3200 in year 44.

  13. Work out the interest earned in year 44 alone

    0.035×£3082.42£107.880.035 \times \pounds 3082.42 \approx \pounds 107.88

    Year 44 earns £107.88\pounds 107.88 of interest -- more than year 11 earned (£87.50)(\pounds 87.50), because the balance it is worked out on is bigger.

  14. Confirm year 55 stays above

    £3505.46>£3200\pounds 3505.46 > \pounds 3200

    The balance keeps growing (£3505.46\pounds 3505.46 after 55 years), so once past £3200\pounds 3200 it stays past it.

  15. State the answer

    n=4n = 4

    After 44 complete years the account is worth more than £3200\pounds 3200 for the first time.

Answer
n=4n = 4
Question 3
6 markschallenging
Amir can invest £3000\pounds 3000 in Account A, which pays 5%5\% compound interest per year, or £3200\pounds 3200 in Account B, which pays 3%3\% compound interest per year. Which account is worth more after 44 years, and by how much?
Show worked solution

Worked solution

  1. Plan the comparison

    A: 3000×1.054vsB: 3200×1.034\text{A: } 3000 \times 1.05^{4} \quad\text{vs}\quad \text{B: } 3200 \times 1.03^{4}

    Account B starts with more money but grows more slowly. Work out both after 44 years. Exam convention: keep the full unrounded balance in the calculator all the way through and round to the nearest penny only at the very end.

  2. Write the yearly percentage as a multiplier

    100%+5%=105%=1.05100\% + 5\% = 105\% = 1.05

    A 5%5\% increase keeps the whole 100%100\% and adds 5%5\% on top, so multiply by 1.051.05 each year.

  3. Balance after year 11

    £3000×1.051=£3150\pounds 3000 \times 1.05^{1} = \pounds 3150

    Year 11: £3000×1.05=£3150\pounds 3000 \times 1.05 = \pounds 3150. This is worked out from the exact starting amount as P×multiplier1P \times \text{multiplier}^{1}, so no rounding error can build up.

  4. Balance after year 22

    £3000×1.052=£3307.50\pounds 3000 \times 1.05^{2} = \pounds 3307.50

    Year 22: £3150×1.05=£3307.50\pounds 3150 \times 1.05 = \pounds 3307.50. This is worked out from the exact starting amount as P×multiplier2P \times \text{multiplier}^{2}, so no rounding error can build up.

  5. Balance after year 33

    £3000×1.053£3472.88\pounds 3000 \times 1.05^{3} \approx \pounds 3472.88

    Year 33: £3307.50×1.05=£3472.88\pounds 3307.50 \times 1.05 = \pounds 3472.88. This is worked out from the exact starting amount as P×multiplier3P \times \text{multiplier}^{3}, so no rounding error can build up.

  6. Balance after year 44

    £3000×1.054£3646.52\pounds 3000 \times 1.05^{4} \approx \pounds 3646.52

    Year 44: £3472.88×1.05=£3646.52\pounds 3472.88 \times 1.05 = \pounds 3646.52. This is worked out from the exact starting amount as P×multiplier4P \times \text{multiplier}^{4}, so no rounding error can build up.

  7. Round Account A to the nearest penny

    £3646.52£3646.52\pounds 3646.52 \to \pounds 3646.52

    Account A finishes on £3646.52\pounds 3646.52.

  8. Write the yearly percentage as a multiplier

    100%+3%=103%=1.03100\% + 3\% = 103\% = 1.03

    A 3%3\% increase keeps the whole 100%100\% and adds 3%3\% on top, so multiply by 1.031.03 each year.

  9. Balance after year 11

    £3200×1.031=£3296\pounds 3200 \times 1.03^{1} = \pounds 3296

    Year 11: £3200×1.03=£3296\pounds 3200 \times 1.03 = \pounds 3296. This is worked out from the exact starting amount as P×multiplier1P \times \text{multiplier}^{1}, so no rounding error can build up.

  10. Balance after year 22

    £3200×1.032=£3394.88\pounds 3200 \times 1.03^{2} = \pounds 3394.88

    Year 22: £3296×1.03=£3394.88\pounds 3296 \times 1.03 = \pounds 3394.88. This is worked out from the exact starting amount as P×multiplier2P \times \text{multiplier}^{2}, so no rounding error can build up.

  11. Balance after year 33

    £3200×1.033£3496.73\pounds 3200 \times 1.03^{3} \approx \pounds 3496.73

    Year 33: £3394.88×1.03=£3496.73\pounds 3394.88 \times 1.03 = \pounds 3496.73. This is worked out from the exact starting amount as P×multiplier3P \times \text{multiplier}^{3}, so no rounding error can build up.

  12. Balance after year 44

    £3200×1.034£3601.63\pounds 3200 \times 1.03^{4} \approx \pounds 3601.63

    Year 44: £3496.73×1.03=£3601.63\pounds 3496.73 \times 1.03 = \pounds 3601.63. This is worked out from the exact starting amount as P×multiplier4P \times \text{multiplier}^{4}, so no rounding error can build up.

  13. Round Account B to the nearest penny

    £3601.63£3601.63\pounds 3601.63 \to \pounds 3601.63

    Account B finishes on £3601.63\pounds 3601.63.

  14. Compare the two accounts and find the difference

    £3646.52£3601.63=£44.89\pounds 3646.52 - \pounds 3601.63 = \pounds 44.89

    Account A ends up worth more -- by £44.89\pounds 44.89 -- even though it started with £200\pounds 200 less.

  15. Explain the result

    1.054=1.21550625vs1.034=1.125508811.05^{4} = 1.21550625 \quad\text{vs}\quad 1.03^{4} = 1.12550881

    Over 44 years Account A multiplies its money by 1.21551.2155 and Account B only by 1.12551.1255. A×1.2155A \times 1.2155 on £3000\pounds 3000 beats B×1.1255B \times 1.1255 on £3200\pounds 3200, so the higher rate wins here -- but note it is close, and with fewer years B would have won.

Answer
Account A, by £44.89\text{Account A, by } \pounds 44.89
Question 4
6 markschallenging
A van costs £30000\pounds 30\,000 when new. It loses 22%22\% of its value in the first year and 12%12\% of its value in each year after that. Work out the value of the van after 55 years, to the nearest penny.
Show worked solution

Worked solution

  1. Plan the calculation

    30000×0.78×0.88430000 \times 0.78 \times 0.88^{4}

    The first year uses a different multiplier from the other four, so it must be done separately and the remaining years compounded on top of it. Exam convention: keep the full unrounded balance in the calculator all the way through and round to the nearest penny only at the very end.

  2. Write the yearly percentage loss as a multiplier

    100%22%=78%=0.78100\% - 22\% = 78\% = 0.78

    Losing 22%22\% each year leaves 78%78\% of the value, so multiply by 0.780.78 each year.

  3. Value after year 11

    £30000×0.78=£23400\pounds 30000 \times 0.78 = \pounds 23400

    A 22%22\% drop in the first year takes the van from £30\pounds 30 000000 to £23400\pounds 23400 -- a loss of £6600\pounds 6600 in one year.

  4. Write the yearly percentage loss as a multiplier

    100%12%=88%=0.88100\% - 12\% = 88\% = 0.88

    Losing 12%12\% each year leaves 88%88\% of the value, so multiply by 0.880.88 each year.

  5. Value after year 22

    £23400×0.881=£20592\pounds 23400 \times 0.88^{1} = \pounds 20592

    Year 22: £23400×0.88=£20592\pounds 23400 \times 0.88 = \pounds 20592. Every year is worked out from the exact year-11 value £23400\pounds 23400, so no rounding error can creep in.

  6. Value after year 33

    £23400×0.882=£18120.96\pounds 23400 \times 0.88^{2} = \pounds 18120.96

    Year 33: £20592×0.88=£18120.96\pounds 20592 \times 0.88 = \pounds 18120.96. Every year is worked out from the exact year-11 value £23400\pounds 23400, so no rounding error can creep in.

  7. Value after year 44

    £23400×0.883£15946.44\pounds 23400 \times 0.88^{3} \approx \pounds 15946.44

    Year 44: £18120.96×0.88=£15946.44\pounds 18120.96 \times 0.88 = \pounds 15946.44. Every year is worked out from the exact year-11 value £23400\pounds 23400, so no rounding error can creep in.

  8. Value after year 55

    £23400×0.884£14032.87\pounds 23400 \times 0.88^{4} \approx \pounds 14032.87

    Year 55: £15946.44×0.88=£14032.87\pounds 15946.44 \times 0.88 = \pounds 14032.87. Every year is worked out from the exact year-11 value £23400\pounds 23400, so no rounding error can creep in.

  9. Round to the nearest penny

    £14032.87£14032.87\pounds 14032.87 \to \pounds 14032.87

    The exact value is rounded to the penny only here, at the end.

  10. Check with a single calculation

    30000×0.78×0.884£14032.8730000 \times 0.78 \times 0.88^{4} \approx \pounds 14032.87

    One calculation gives the same value as the table, which confirms it.

  11. Reject the wrong method

    30000×0.885£15831.9630000 \times 0.88^{5} \approx \pounds 15831.96

    Using 12%12\% for all five years gives £15831.96\pounds 15831.96, which is far too big -- it ignores the extra 1010 percentage points lost in the first year.

  12. Compare the yearly losses

    year 1: £6600year 2: £2808\text{year 1: } \pounds 6600 \quad\text{year 2: } \pounds 2808

    The van loses £6600\pounds 6600 in year 11 but only £2808\pounds 2808 in year 22. The percentage is applied to a smaller value each year, so the cash loss shrinks every year -- which is why the value never reaches zero.

  13. Work out the total value lost

    £30000£14032.87=£15967.13\pounds 30000 - \pounds 14032.87 = \pounds 15967.13

    The van has lost £15967.13\pounds 15967.13 of its value in 55 years.

  14. Work out the loss as a fraction of the price

    £15967.13£30000×10053.22%\frac{\pounds 15967.13}{\pounds 30000} \times 100 \approx 53.22\%

    The van has lost about 53.2%53.2\% of its value -- just over half -- which is a sensible size for a five-year-old van.

  15. State the answer

    £14032.87\pounds 14032.87

    After 55 years the van is worth £14032.87\pounds 14032.87.

Answer
£14032.87\pounds 14032.87
Question 5
6 markschallenging
£8000\pounds 8000 is invested at 4.5%4.5\% compound interest per year. Work out the interest earned in the fifth year alone. Give your answer to the nearest penny.
Show worked solution

Worked solution

  1. Understand what is being asked

    interest in year 5=(balance after 5 years)(balance after 4 years)\text{interest in year 5} = (\text{balance after 5 years}) - (\text{balance after 4 years})

    The interest earned in year 55 alone is 4.5%4.5\% of the balance at the START of year 55, which is the balance at the end of year 44. Exam convention: keep the full unrounded balance in the calculator all the way through and round to the nearest penny only at the very end.

  2. Write the yearly percentage as a multiplier

    100%+4.5%=104.5%=1.045100\% + 4.5\% = 104.5\% = 1.045

    A 4.5%4.5\% increase keeps the whole 100%100\% and adds 4.5%4.5\% on top, so multiply by 1.0451.045 each year.

  3. Balance after year 11

    £8000×1.0451=£8360\pounds 8000 \times 1.045^{1} = \pounds 8360

    Year 11: £8000×1.045=£8360\pounds 8000 \times 1.045 = \pounds 8360. This is worked out from the exact starting amount as P×multiplier1P \times \text{multiplier}^{1}, so no rounding error can build up.

  4. Balance after year 22

    £8000×1.0452=£8736.20\pounds 8000 \times 1.045^{2} = \pounds 8736.20

    Year 22: £8360×1.045=£8736.20\pounds 8360 \times 1.045 = \pounds 8736.20. This is worked out from the exact starting amount as P×multiplier2P \times \text{multiplier}^{2}, so no rounding error can build up.

  5. Balance after year 33

    £8000×1.0453£9129.33\pounds 8000 \times 1.045^{3} \approx \pounds 9129.33

    Year 33: £8736.20×1.045=£9129.33\pounds 8736.20 \times 1.045 = \pounds 9129.33. This is worked out from the exact starting amount as P×multiplier3P \times \text{multiplier}^{3}, so no rounding error can build up.

  6. Balance after year 44

    £8000×1.0454£9540.15\pounds 8000 \times 1.045^{4} \approx \pounds 9540.15

    Year 44: £9129.33×1.045=£9540.15\pounds 9129.33 \times 1.045 = \pounds 9540.15. This is worked out from the exact starting amount as P×multiplier4P \times \text{multiplier}^{4}, so no rounding error can build up.

  7. Note the exact balance at the start of year 55

    £9540.15 (exact: 9540.148805000000)\pounds 9540.15 \text{ (exact: } 9540.148805000000 \text{)}

    This exact value is what year 55 interest is worked out on -- rounding it to the penny first would give a slightly different answer.

  8. Balance after year 55

    £8000×1.0455£9969.46\pounds 8000 \times 1.045^{5} \approx \pounds 9969.46

    Year 55: £9540.15×1.045=£9969.46\pounds 9540.15 \times 1.045 = \pounds 9969.46. This is worked out from the exact starting amount as P×multiplier5P \times \text{multiplier}^{5}, so no rounding error can build up.

  9. Subtract to find the year 55 interest

    £9969.46£9540.15£429.31\pounds 9969.46 - \pounds 9540.15 \approx \pounds 429.31

    The interest earned in year 55 alone is £429.31\pounds 429.31.

  10. Check it directly as a percentage

    0.045×£9540.15£429.310.045 \times \pounds 9540.15 \approx \pounds 429.31

    4.5%4.5\% of the start-of-year-55 balance gives the same answer, which confirms it.

  11. Compare with year 11

    0.045×£8000=£3600.045 \times \pounds 8000 = \pounds 360

    In year 11 the account earned only £360\pounds 360. Year 55 earns £429.31\pounds 429.31 -- more, because the balance it is worked out on is bigger.

  12. Explain the growth in the yearly interest

    £429.31£3601.0454\frac{\pounds 429.31}{\pounds 360} \approx 1.045^{4}

    Each year's interest is 1.0451.045 times the year before, because the balance it is charged on is 1.0451.045 times bigger. After 44 years of that, year 55 interest is 1.04541.045^4 times the year 11 interest.

  13. Reject the simple-interest answer

    4.5100×8000=£360\frac{4.5}{100} \times 8000 = \pounds 360

    A simple-interest account would pay exactly £360\pounds 360 in year 55 as well. The compound answer is bigger, so the two are genuinely different -- do not confuse them.

  14. Round to the nearest penny

    £429.31£429.31\pounds 429.31 \to \pounds 429.31

    The exact difference is rounded to the penny once, at the end.

  15. State the answer

    £429.31\pounds 429.31

    The interest earned in year 55 alone is £429.31\pounds 429.31.

Answer
£429.31\pounds 429.31

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