Direct and inverse proportion Worked Solutions — GCSE Maths

Fully worked, step-by-step solutions to GCSE Direct and inverse proportion questions. See exactly how to solve problems on direct proportion, constant of proportionality, finding k, substitution.

direct proportionconstant of proportionalityfinding ksubstitutioninverse proportionrecognising graphs
GCSE Foundation70 questionsStep-by-step solutions
Question 1
1 markeasy
yy is directly proportional to xx. When x=4x = 4, y=20y = 20. Work out the value of kk in the formula y=kxy = kx.

Worked solution

  1. Identify the type of proportion

    yxy \propto x

    Directly proportional means y=kxy = kx: multiply xx by a number and yy is multiplied by the same number.

  2. Write the general formula

    y=kxy = kx

    Here kk is the constant of proportionality. It is the same for every pair of values in the relationship.

  3. Divide y by x to find k

    k=204=5k = \frac{20}{4} = 5

    For direct proportion k=yxk = \frac{y}{x}, so k=20÷4=5k = 20 \div 4 = 5.

Answer
55
Question 2
2 markseasy
yy is directly proportional to xx. When x=3x = 3, y=15y = 15. Work out the value of yy when x=7x = 7.

Worked solution

  1. Identify the type of proportion

    yxy \propto x

    Directly proportional means y=kxy = kx: multiply xx by a number and yy is multiplied by the same number.

  2. Find the constant of proportionality

    k=153=5k = \frac{15}{3} = 5

    Divide yy by xx: k=5k = 5, so y=5xy = 5x.

  3. Substitute x=7x = 7

    y=5×7=35y = 5 \times 7 = 35

    So y=35y = 35 when x=7x = 7.

Answer
3535
Question 3
1 markeasy
yy is inversely proportional to xx. When x=5x = 5, y=6y = 6. Work out the value of kk in the formula y=kxy = \frac{k}{x}.

Worked solution

  1. Identify the type of proportion

    y1xy \propto \frac{1}{x}

    Inversely proportional means y=kxy = \frac{k}{x}: multiply xx by a number and yy is divided by that number.

  2. Write the general formula

    y=kxsok=xyy = \frac{k}{x} \quad \text{so} \quad k = xy

    Here kk is the constant of proportionality. For inverse proportion the product x×yx \times y is always the same.

  3. Multiply x by y to find k

    k=5×6=30k = 5 \times 6 = 30

    For inverse proportion k=xyk = xy, so k=30k = 30.

Answer
3030
Question 4
2 markseasy
yy is inversely proportional to xx. When x=4x = 4, y=9y = 9. Work out the value of yy when x=6x = 6.

Worked solution

  1. Identify the type of proportion

    y1xy \propto \frac{1}{x}

    Inversely proportional means y=kxy = \frac{k}{x}: multiply xx by a number and yy is divided by that number.

  2. Find the constant of proportionality

    k=4×9=36k = 4 \times 9 = 36

    The product xyxy is constant, so k=36k = 36 and y=36xy = \frac{36}{x}.

  3. Substitute x=6x = 6

    y=366=6y = \frac{36}{6} = 6

    So y=6y = 6 when x=6x = 6.

Answer
66
Question 5
1 markeasy
yy is directly proportional to xx. Which one of these describes the graph of yy against xx?

Worked solution

  1. Write down what direct proportion means

    y=kxy = kx

    Direct proportion always has the form y=kxy = kx.

  2. Find the value of y when x is zero

    x=0y=k×0=0x = 0 \Rightarrow y = k \times 0 = 0

    The graph must pass through the origin (0,0)(0, 0).

  3. Describe the shape

    y=kx is a straight line through (0,0)y = kx \text{ is a straight line through } (0,0)

    A constant gradient kk gives a straight line, and it goes through the origin.

Answer
A straight line through the origin\text{A straight line through the origin}

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