GCSE Rounding Practice Questions

Free GCSE Rounding practice questions with full step-by-step worked solutions. Covers rounding, dp, nearest, sf. Practise exam-style problems and check your method.

roundingdpnearestsfsignificant figuresdecimal places
GCSE Foundation70 questionsStep-by-step solutions
Question 1
1 markeasy
Round 3.473.47 to the 11 decimal place.
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Worked solution

  1. Identify the first decimal place (tenths)

    3.473.47

    We are rounding 3.473.47 to the 11 decimal place, so we focus on the first decimal place (tenths).

  2. Look at the next digit to decide

    next digit=7\text{next digit} = 7

    The next digit is 77, which is 55 or more, so we round up.

  3. Write 3.473.47 rounded to the 11 decimal place

    3.473.53.47 \approx 3.5

    So 3.473.47 rounded to the 11 decimal place is 3.53.5.

Answer
3.53.5
Question 2
1 markeasy
Round 0.00720.0072 to the 11 significant figure.
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Worked solution

  1. Identify the 11 significant figure

    0.00720.0072

    We are rounding 0.00720.0072 to the 11 significant figure, so we focus on the 11 significant figure.

  2. Look at the next digit to decide

    next digit=2\text{next digit} = 2

    The next digit is 22, which is less than 55, so we round down.

  3. Write 0.00720.0072 rounded to the 11 significant figure

    0.00720.0070.0072 \approx 0.007

    So 0.00720.0072 rounded to the 11 significant figure is 0.0070.007.

Answer
0.0070.007
Question 3
2 marksintermediate
Round 0.84710.8471 to 22 decimal places.
Show worked solution

Worked solution

  1. Identify the second decimal place (hundredths)

    0.84710.8471

    We keep 2 digit(s) after the decimal point.

  2. Look at the next digit

    next digit=7\text{next digit} = 7

    This digit decides whether we round up or leave the kept digit unchanged.

  3. Apply the rounding rule

    757 \geq 5

    The next digit is 77, which is 55 or more, so we round up.

  4. Adjust the kept digits, carrying if needed

    0.84710.850.8471 \to 0.85

    If rounding up makes a 99 become 1010, carry into the next column.

  5. Keep any trailing zeros in the decimal part

    0.850.85

    Trailing zeros are kept so the answer clearly shows 2 decimal place(s).

  6. Write 0.8471 to 2 decimal place(s)

    0.84710.850.8471 \approx 0.85

    So 0.8471 rounded to 2 decimal place(s) is 0.85.

Answer
0.850.85
Question 4
3 markshard
Four towns are surveyed. By rounding each value to the nearest 100100, estimate the total of 33653365, 44714471, 33373337, 25622562.
Show worked solution

Worked solution

  1. Look at 33653365 to round to the nearest 100100

    3365 (deciding digit 6)3365\ (\text{deciding digit } 6)

    The next digit is 66, which is 55 or more, so we round up.

  2. Round 33653365

    336534003365 \approx 3400

    33653365 rounds to 34003400.

  3. Look at 44714471 to round to the nearest 100100

    4471 (deciding digit 7)4471\ (\text{deciding digit } 7)

    The next digit is 77, which is 55 or more, so we round up.

  4. Round 44714471

    447145004471 \approx 4500

    44714471 rounds to 45004500.

  5. Look at 33373337 to round to the nearest 100100

    3337 (deciding digit 3)3337\ (\text{deciding digit } 3)

    The next digit is 33, which is less than 55, so we round down.

  6. Round 33373337

    333733003337 \approx 3300

    33373337 rounds to 33003300.

  7. Look at 25622562 to round to the nearest 100100

    2562 (deciding digit 6)2562\ (\text{deciding digit } 6)

    The next digit is 66, which is 55 or more, so we round up.

  8. Round 25622562

    256226002562 \approx 2600

    25622562 rounds to 26002600.

  9. Add the rounded values

    3400+4500+3300+26003400 + 4500 + 3300 + 2600

    Add the rounded numbers to estimate the total.

  10. State the estimate

    =13800= 13800

    The estimated total is 1380013800.

Answer
1380013800
Question 5
5 markschallenging
Six stages of a race are timed. By rounding each value to the 11 significant figure, estimate the total of 283.1283.1, 787.1787.1, 752.0752.0, 536.2536.2, 456.8456.8, 68.268.2.
Show worked solution

Worked solution

  1. Look at 283.1283.1 to round to the 11 significant figure

    283.1 (deciding digit 8)283.1\ (\text{deciding digit } 8)

    The next digit is 88, which is 55 or more, so we round up.

  2. Round 283.1283.1

    283.1300283.1 \approx 300

    283.1283.1 rounds to 300300.

  3. Look at 787.1787.1 to round to the 11 significant figure

    787.1 (deciding digit 8)787.1\ (\text{deciding digit } 8)

    The next digit is 88, which is 55 or more, so we round up.

  4. Round 787.1787.1

    787.1800787.1 \approx 800

    787.1787.1 rounds to 800800.

  5. Look at 752.0752.0 to round to the 11 significant figure

    752.0 (deciding digit 5)752.0\ (\text{deciding digit } 5)

    The next digit is 55, which is 55 or more, so we round up.

  6. Round 752.0752.0

    752.0800752.0 \approx 800

    752.0752.0 rounds to 800800.

  7. Look at 536.2536.2 to round to the 11 significant figure

    536.2 (deciding digit 3)536.2\ (\text{deciding digit } 3)

    The next digit is 33, which is less than 55, so we round down.

  8. Round 536.2536.2

    536.2500536.2 \approx 500

    536.2536.2 rounds to 500500.

  9. Look at 456.8456.8 to round to the 11 significant figure

    456.8 (deciding digit 5)456.8\ (\text{deciding digit } 5)

    The next digit is 55, which is 55 or more, so we round up.

  10. Round 456.8456.8

    456.8500456.8 \approx 500

    456.8456.8 rounds to 500500.

  11. Look at 68.268.2 to round to the 11 significant figure

    68.2 (deciding digit 8)68.2\ (\text{deciding digit } 8)

    The next digit is 88, which is 55 or more, so we round up.

  12. Round 68.268.2

    68.27068.2 \approx 70

    68.268.2 rounds to 7070.

  13. Add the first group of rounded values

    300+800+800=1900300 + 800 + 800 = 1900

    Add the first half of the rounded numbers.

  14. Add the second group of rounded values

    500+500+70=1070500 + 500 + 70 = 1070

    Add the second half of the rounded numbers.

  15. Combine the two subtotals

    1900+1070=29701900 + 1070 = 2970

    The estimated total is 29702970.

Answer
29702970

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