Hard GCSE Powers and roots Questions

Challenging, exam-style GCSE Powers and roots questions with worked solutions. Stretch yourself on the hardest powers, square roots, ordering, roots problems.

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GCSE Foundation34 questionsStep-by-step solutions
Question 1
5 markschallenging
A square patio is made from 196196 identical square tiles arranged in a square. (a) How many tiles are along each side? (b) How many tiles lie on the border (edge) of the patio?
Show worked solution

Worked solution

  1. Link tiles to a square array

    side2=196\text{side}^2 = 196

    A square arrangement means side x side tiles.

  2. Find the side

    side=196\text{side} = \sqrt{196}

    Take the square root of 196196.

  3. Try a number just below

    132=16913^2 = 169

    Testing 1313 gives 169169, which is too small.

  4. Try the next number

    142=19614^2 = 196

    Testing 1414 gives exactly 196196, so this is the root.

  5. Verify by multiplying back

    14×14=19614 \times 14 = 196

    Check the root by squaring it back to 196196.

  6. Split the second number by place value

    14×14=14×10+14×414 \times 14 = 14 \times 10 + 14 \times 4

    Break 1414 into 10+410 + 4 so we can multiply in easy parts.

  7. Multiply the tens part

    14×10=14014 \times 10 = 140

    First multiply by the 1010.

  8. Multiply the units part

    14×4=5614 \times 4 = 56

    Then multiply by the 44.

  9. Add the two parts

    140+56=196140 + 56 = 196

    Add the partial products to get 196196.

  10. State part (a)

    14 tiles per side14 \text{ tiles per side}

    Each side has 1414 tiles.

  11. Set up the border count

    4×144 \times 14

    Four sides of 1414 tiles each is a first estimate.

  12. Multiply

    4×14=564 \times 14 = 56

    That gives 5656.

  13. Adjust for corners

    564=5256 - 4 = 52

    The 44 corner tiles were counted twice, so subtract 44.

  14. State part (b)

    52 border tiles52 \text{ border tiles}

    There are 5252 tiles on the border.

  15. Sense check

    142122=196144=5214^2 - 12^2 = 196 - 144 = 52

    Total tiles minus the 1212x122 interior also gives 5252 border tiles.

  16. Final answer

    5252

    The requested final answer is the border count, 5252.

Answer
5252
Question 2
5 markschallenging
Starting from 11, one process doubles each step and another triples each step. After 55 steps, which is larger and by how much: 252^5 or 353^5?
Show worked solution

Worked solution

  1. Set up the doubling

    start 1, ×2 each step\text{start } 1,\ \times 2 \text{ each step}

    Doubling means multiply by 22 every step.

  2. Doubling steps 11 to 33

    12481\to2\to4\to8

    After three steps the value is 88.

  3. Doubling steps 44 to 55

    816328\to16\to32

    After five steps the value is 32=2532 = 2^5.

  4. Set up the tripling

    start 1, ×3 each step\text{start } 1,\ \times 3 \text{ each step}

    Tripling means multiply by 33 every step.

  5. Tripling steps 11 to 33

    139271\to3\to9\to27

    After three steps the value is 2727.

  6. Tripling steps 44 to 55

    278124327\to81\to243

    After five steps the value is 243=35243 = 3^5.

  7. Compare the totals

    243>32243 > 32

    The tripling result is larger.

  8. Identify the larger

    353^5

    So 353^5 is the larger.

  9. Find the difference

    24332=211243 - 32 = 211

    Subtract to see by how much.

  10. State the answer

    35 is larger by 2113^5 \text{ is larger by } 211

    353^5 beats 252^5 by 211211.

  11. Watch the gap grow

    1 step: 32=1, 2 steps: 94=51\text{ step: }3-2=1,\ 2\text{ steps: }9-4=5

    Early on the gap is tiny, then it widens fast.

  12. Continue the gap

    3 steps: 278=19, 5 steps: 24332=2113\text{ steps: }27-8=19,\ 5\text{ steps: }243-32=211

    The gap balloons because tripling multiplies by more each time.

  13. Reason about growth

    tripling grows faster than doubling\text{tripling grows faster than doubling}

    A larger multiplier each step makes the gap widen quickly.

  14. Sense check

    243÷327.6243 \div 32 \approx 7.6

    353^5 is more than seven times 252^5, so the large gap makes sense.

  15. Underline the final answer

    = 35=2433^5 = 243 is larger, by 211211.

    Write the answer on its own line so it is clear and easy to mark.

Answer
35=2433^5 = 243 is larger, by 211211.
Question 3
4 markschallenging
625625 is a power of 55. Which power of 55 is it, that is what is the value of k in 5k=6255^k = 625?
Show worked solution

Worked solution

  1. Understand the task

    5k=6255^k = 625

    We need the number of 55s that multiply to 625625.

  2. First power

    51=55^1 = 5

    One 55.

  3. Second power

    52=255^2 = 25

    5×5=255 \times 5 = 25.

  4. Third power

    5×25=1255 \times 25 = 125

    53=1255^3 = 125.

  5. Fourth power

    5×125=6255 \times 125 = 625

    54=6255^4 = 625.

  6. Match to the target

    54=6255^4 = 625

    This equals the target 625625.

  7. State k

    k=4k = 4

    So the power is 44.

  8. Verify with place value

    25×25=62525 \times 25 = 625

    Since 54=(52)2=2525^4 = (5^2)^2 = 25^2, check 2525 x 2525.

  9. Multiply the tens part

    25×20=50025 \times 20 = 500

    Break 2525 into 20+520 + 5; first the 2020.

  10. Multiply the units part

    25×5=12525 \times 5 = 125

    Then the 55.

  11. Add the parts

    500+125=625500 + 125 = 625

    The parts add to 625625, confirming 252=62525^2 = 625.

  12. Express another way

    625=(52)2=252625 = (5^2)^2 = 25^2

    So 625625 is also the square of 2525.

  13. Reject the near-miss

    53=1256255^3 = 125 \neq 625

    The common wrong answer k=3k = 3 gives only 125125.

  14. Conclude

    625=54625 = 5^4

    625625 is the 44th power of 55, so k=4k = 4.

  15. Underline the final answer

    = k=4k = 4 (since 54=6255^4 = 625)

    Write the answer on its own line so it is clear and easy to mark.

Answer
k=4k = 4 (since 54=6255^4 = 625)
Question 4
4 markschallenging
The square numbers are 11, 44, 99, 1616, 2525, ... . What is the 1010th square number?
Show worked solution

Worked solution

  1. Spot the rule

    n-th square=n2\text{n-th square} = n^2

    The n-th square number is n squared.

  2. List the first five squares

    12=1, 22=4, 32=9, 42=16, 52=251^2=1,\ 2^2=4,\ 3^2=9,\ 4^2=16,\ 5^2=25

    These are the first five terms given.

  3. Continue the list

    62=36, 72=49, 82=64, 92=81, 102=1006^2=36,\ 7^2=49,\ 8^2=64,\ 9^2=81,\ 10^2=100

    Carry on to the tenth term.

  4. Count to the 1010th term

    10th=102\text{10th} = 10^2

    The tenth square uses n=10n = 10.

  5. Compute directly

    10×10=10010 \times 10 = 100

    10×10=10010 \times 10 = 100.

  6. State the answer

    100100

    The 1010th square number is 100100.

  7. Check another way: odd-number sums

    1,1+3,1+3+5,1, 1+3, 1+3+5, \dots

    Each square is the running total of the odd numbers.

  8. Explain the pattern

    n2=1+3+5++(2n1)n^2 = 1+3+5+\dots+(2n-1)

    The n-th square is the sum of the first n odd numbers.

  9. Write the first ten odd numbers

    1,3,5,7,9,11,13,15,17,191,3,5,7,9,11,13,15,17,19

    These are the ten odds we must add.

  10. Add in stages

    1+3+5+7+9=251+3+5+7+9 = 25

    The first five odds total 2525.

  11. Add the next five

    11+13+15+17+19=7511+13+15+17+19 = 75

    The next five odds total 7575.

  12. Combine

    25+75=10025 + 75 = 100

    The ten odd numbers total 100100.

  13. Cross-check with the rule

    102=10010^2 = 100

    Both methods give 100100.

  14. Interpret as an array

    10×10 grid10 \times 10 \text{ grid}

    100100 is the number of dots in a 1010 by 1010 square array.

  15. Conclude

    10th square=100\text{10th square} = 100

    So the 1010th square number is 100100.

Answer
100100
Question 5
5 markschallenging
A square field has an area of 1000010000 m2m^2. Fencing costs 55 pounds per metre. Work out the cost of fencing the perimeter.
Show worked solution

Worked solution

  1. Link area to side

    area=side2\text{area} = \text{side}^2

    Area of a square is side squared.

  2. Set up the root

    side=10000\text{side} = \sqrt{10000}

    Take the square root of the area.

  3. Test 100100

    1002=10000100^2 = 10000

    100×100=10000100 \times 100 = 10000.

  4. State the side

    side=100 m\text{side} = 100\text{ m}

    Each side is 100100 m.

  5. Recall perimeter

    P=4×sideP = 4 \times \text{side}

    A square has four equal sides.

  6. Compute the perimeter

    4×100=4004 \times 100 = 400

    The perimeter is 400400 m.

  7. Multiply by the cost

    400×5=2000400 \times 5 = 2000

    Each metre costs 55 pounds.

  8. State the cost

    £2000\pounds 2000

    The fencing costs 20002000 pounds.

  9. Sense check

    1002=10000100^2 = 10000

    The side gives back the area, so the working is consistent.

  10. Underline the final answer

    =£2000= £2000

    Write the answer on its own line so it is clear and easy to mark.

  11. Check it answers the question asked

    £2000£2000

    Re-reading the question, £20002000 is exactly the quantity required.

  12. Sense-check the size

    £2000£2000

    The size of £20002000 is sensible for this calculation, so no slip has been made.

  13. Confirm the answer is exact

    £2000£2000

    Because the numbers are perfect powers or roots, £20002000 is exact and needs no rounding.

  14. Recap the method

    £2000£2000

    The method was: apply the definition, work step by step, then check, giving £20002000.

  15. Check no factor was dropped

    £2000£2000

    Counting the factors used matches the power, confirming £20002000.

Answer
£2000£2000

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