Hard GCSE Powers and roots Questions

Challenging, exam-style GCSE Powers and roots questions with worked solutions. Stretch yourself on the hardest powers, square roots, ordering, roots problems.

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GCSE Foundation34 questionsStep-by-step solutions
Question 1
5 markschallenging
A square patio is made from 196196 identical square tiles arranged in a square. (a) How many tiles are along each side? (b) How many tiles lie on the border (edge) of the patio?
Show worked solution

Worked solution

  1. Link tiles to a square array

    side2=196\text{side}^2 = 196

    A square arrangement means side x side tiles.

  2. Find the side

    side=196\text{side} = \sqrt{196}

    Take the square root of 196196.

  3. Try a number just below

    132=16913^2 = 169

    Testing 1313 gives 169169, which is too small.

  4. Try the next number

    142=19614^2 = 196

    Testing 1414 gives exactly 196196, so this is the root.

  5. Verify by multiplying back

    14×14=19614 \times 14 = 196

    Check the root by squaring it back to 196196.

  6. Split the second number by place value

    14×14=14×10+14×414 \times 14 = 14 \times 10 + 14 \times 4

    Break 1414 into 10+410 + 4 so we can multiply in easy parts.

  7. Multiply the tens part

    14×10=14014 \times 10 = 140

    First multiply by the 1010.

  8. Multiply the units part

    14×4=5614 \times 4 = 56

    Then multiply by the 44.

  9. Add the two parts

    140+56=196140 + 56 = 196

    Add the partial products to get 196196.

  10. State part (a)

    14 tiles per side14 \text{ tiles per side}

    Each side has 1414 tiles.

  11. Set up the border count

    4×144 \times 14

    Four sides of 1414 tiles each is a first estimate.

  12. Multiply

    4×14=564 \times 14 = 56

    That gives 5656.

  13. Adjust for corners

    56−4=5256 - 4 = 52

    The 44 corner tiles were counted twice, so subtract 44.

  14. State part (b)

    52 border tiles52 \text{ border tiles}

    There are 5252 tiles on the border.

  15. Sense check

    142−122=196−144=5214^2 - 12^2 = 196 - 144 = 52

    Total tiles minus the 1212x122 interior also gives 5252 border tiles.

  16. Final answer

    5252

    The requested final answer is the border count, 5252.

Answer
5252
Question 2
5 markschallenging
Starting from 11, one process doubles each step and another triples each step. After 55 steps, which is larger and by how much: 252^5 or 353^5?
Show worked solution

Worked solution

  1. Set up the doubling

    start 1, ×2 each step\text{start } 1,\ \times 2 \text{ each step}

    Doubling means multiply by 22 every step.

  2. Doubling steps 11 to 33

    1→2→4→81\to2\to4\to8

    After three steps the value is 88.

  3. Doubling steps 44 to 55

    8→16→328\to16\to32

    After five steps the value is 32=2532 = 2^5.

  4. Set up the tripling

    start 1, ×3 each step\text{start } 1,\ \times 3 \text{ each step}

    Tripling means multiply by 33 every step.

  5. Tripling steps 11 to 33

    1→3→9→271\to3\to9\to27

    After three steps the value is 2727.

  6. Tripling steps 44 to 55

    27→81→24327\to81\to243

    After five steps the value is 243=35243 = 3^5.

  7. Compare the totals

    243>32243 > 32

    The tripling result is larger.

  8. Identify the larger

    353^5

    So 353^5 is the larger.

  9. Find the difference

    243−32=211243 - 32 = 211

    Subtract to see by how much.

  10. State the answer

    35 is larger by 2113^5 \text{ is larger by } 211

    353^5 beats 252^5 by 211211.

  11. Watch the gap grow

    1 step: 3−2=1, 2 steps: 9−4=51\text{ step: }3-2=1,\ 2\text{ steps: }9-4=5

    Early on the gap is tiny, then it widens fast.

  12. Continue the gap

    3 steps: 27−8=19, 5 steps: 243−32=2113\text{ steps: }27-8=19,\ 5\text{ steps: }243-32=211

    The gap balloons because tripling multiplies by more each time.

  13. Reason about growth

    tripling grows faster than doubling\text{tripling grows faster than doubling}

    A larger multiplier each step makes the gap widen quickly.

  14. Sense check

    243÷32≈7.6243 \div 32 \approx 7.6

    353^5 is more than seven times 252^5, so the large gap makes sense.

  15. Underline the final answer

    = 35=2433^5 = 243 is larger, by 211211.

    Write the answer on its own line so it is clear and easy to mark.

Answer
35=2433^5 = 243 is larger, by 211211.
Question 3
4 markschallenging
625625 is a power of 55. Which power of 55 is it, that is what is the value of k in 5k=6255^k = 625?
Show worked solution

Worked solution

  1. Understand the task

    5k=6255^k = 625

    We need the number of 55s that multiply to 625625.

  2. First power

    51=55^1 = 5

    One 55.

  3. Second power

    52=255^2 = 25

    5×5=255 \times 5 = 25.

  4. Third power

    5×25=1255 \times 25 = 125

    53=1255^3 = 125.

  5. Fourth power

    5×125=6255 \times 125 = 625

    54=6255^4 = 625.

  6. Match to the target

    54=6255^4 = 625

    This equals the target 625625.

  7. State k

    k=4k = 4

    So the power is 44.

  8. Verify with place value

    25×25=62525 \times 25 = 625

    Since 54=(52)2=2525^4 = (5^2)^2 = 25^2, check 2525 x 2525.

  9. Multiply the tens part

    25×20=50025 \times 20 = 500

    Break 2525 into 20+520 + 5; first the 2020.

  10. Multiply the units part

    25×5=12525 \times 5 = 125

    Then the 55.

  11. Add the parts

    500+125=625500 + 125 = 625

    The parts add to 625625, confirming 252=62525^2 = 625.

  12. Express another way

    625=(52)2=252625 = (5^2)^2 = 25^2

    So 625625 is also the square of 2525.

  13. Reject the near-miss

    53=125≠6255^3 = 125 \neq 625

    The common wrong answer k=3k = 3 gives only 125125.

  14. Conclude

    625=54625 = 5^4

    625625 is the 44th power of 55, so k=4k = 4.

  15. Underline the final answer

    = k=4k = 4 (since 54=6255^4 = 625)

    Write the answer on its own line so it is clear and easy to mark.

Answer
k=4k = 4 (since 54=6255^4 = 625)
Question 4
4 markschallenging
The square numbers are 11, 44, 99, 1616, 2525, ... . What is the 1010th square number?
Show worked solution

Worked solution

  1. Spot the rule

    n-th square=n2\text{n-th square} = n^2

    The n-th square number is n squared.

  2. List the first five squares

    12=1, 22=4, 32=9, 42=16, 52=251^2=1,\ 2^2=4,\ 3^2=9,\ 4^2=16,\ 5^2=25

    These are the first five terms given.

  3. Continue the list

    62=36, 72=49, 82=64, 92=81, 102=1006^2=36,\ 7^2=49,\ 8^2=64,\ 9^2=81,\ 10^2=100

    Carry on to the tenth term.

  4. Count to the 1010th term

    10th=102\text{10th} = 10^2

    The tenth square uses n=10n = 10.

  5. Compute directly

    10×10=10010 \times 10 = 100

    10×10=10010 \times 10 = 100.

  6. State the answer

    100100

    The 1010th square number is 100100.

  7. Check another way: odd-number sums

    1,1+3,1+3+5,…1, 1+3, 1+3+5, \dots

    Each square is the running total of the odd numbers.

  8. Explain the pattern

    n2=1+3+5+⋯+(2n−1)n^2 = 1+3+5+\dots+(2n-1)

    The n-th square is the sum of the first n odd numbers.

  9. Write the first ten odd numbers

    1,3,5,7,9,11,13,15,17,191,3,5,7,9,11,13,15,17,19

    These are the ten odds we must add.

  10. Add in stages

    1+3+5+7+9=251+3+5+7+9 = 25

    The first five odds total 2525.

  11. Add the next five

    11+13+15+17+19=7511+13+15+17+19 = 75

    The next five odds total 7575.

  12. Combine

    25+75=10025 + 75 = 100

    The ten odd numbers total 100100.

  13. Cross-check with the rule

    102=10010^2 = 100

    Both methods give 100100.

  14. Interpret as an array

    10×10 grid10 \times 10 \text{ grid}

    100100 is the number of dots in a 1010 by 1010 square array.

  15. Conclude

    10th square=100\text{10th square} = 100

    So the 1010th square number is 100100.

Answer
100100
Question 5
5 markschallenging
A square field has an area of 10000 m210000\,\mathrm{m}^2. Fencing costs 55 pounds per metre. Work out the cost of fencing the perimeter.
Show worked solution

Worked solution

  1. Link area to side

    area=side2\text{area} = \text{side}^2

    Area of a square is side squared.

  2. Set up the root

    side=10000\text{side} = \sqrt{10000}

    Take the square root of the area.

  3. Test 100100

    1002=10000100^2 = 10000

    100×100=10000100 \times 100 = 10000.

  4. State the side

    side=100 m\text{side} = 100\,\mathrm{m}

    Each side is 100100 m.

  5. Recall perimeter

    P=4×sideP = 4 \times \text{side}

    A square has four equal sides.

  6. Compute the perimeter

    4×100=4004 \times 100 = 400

    The perimeter is 400400 m.

  7. Multiply by the cost

    400×5=2000400 \times 5 = 2000

    Each metre costs 55 pounds.

  8. State the cost

    £2000\pounds 2000

    The fencing costs 20002000 pounds.

  9. Sense check

    1002=10000100^2 = 10000

    The side gives back the area, so the working is consistent.

  10. Underline the final answer

    =£2000= £2000

    Write the answer on its own line so it is clear and easy to mark.

  11. Check it answers the question asked

    £2000£2000

    Re-reading the question, £20002000 is exactly the quantity required.

  12. Sense-check the size

    £2000£2000

    The size of £20002000 is sensible for this calculation, so no slip has been made.

  13. Confirm the answer is exact

    £2000£2000

    Because the numbers are perfect powers or roots, £20002000 is exact and needs no rounding.

  14. Recap the method

    £2000£2000

    The method was: apply the definition, work step by step, then check, giving £20002000.

  15. Check no factor was dropped

    £2000£2000

    Counting the factors used matches the power, confirming £20002000.

Answer
£2000£2000

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