Exact calculation Worked Solutions — GCSE Maths

Fully worked, step-by-step solutions to GCSE Exact calculation questions. See exactly how to solve problems on adding fractions, same denominator, subtracting fractions, simplifying.

adding fractionssame denominatorsubtracting fractionssimplifyingmultiplying fractionsmultiples of pi
GCSE Foundation70 questionsStep-by-step solutions
Question 1
1 markeasy
Work out 15+25\frac{1}{5} + \frac{2}{5}. Give your answer as a fraction.

Worked solution

  1. Check the denominators

    15+25\frac{1}{5} + \frac{2}{5}

    Both fractions are in fifths, so they can be added straight away.

  2. Add the numerators

    1+25=35\frac{1+2}{5} = \frac{3}{5}

    When the denominators match, add the tops and keep the bottom the same.

  3. State the exact answer

    35\frac{3}{5}

    Three fifths is already in its simplest form — an exact answer, not a rounded decimal.

Answer
35\frac{3}{5}
Question 2
1 markeasy
Work out 3414\frac{3}{4} - \frac{1}{4}. Give your answer in its simplest form.

Worked solution

  1. Check the denominators

    3414\frac{3}{4} - \frac{1}{4}

    Both fractions are in quarters, so they can be subtracted straight away.

  2. Subtract the numerators

    314=24\frac{3-1}{4} = \frac{2}{4}

    Take the tops away and keep the bottom the same.

  3. Simplify

    24=12\frac{2}{4} = \frac{1}{2}

    Divide top and bottom by 22 to give the simplest form, one half.

Answer
12\frac{1}{2}
Question 3
1 markeasy
Work out 12×13\frac{1}{2} \times \frac{1}{3}.

Worked solution

  1. Recall the multiplication rule

    ab×cd=acbd\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}

    To multiply fractions, multiply the tops together and the bottoms together.

  2. Multiply tops and bottoms

    1×12×3=16\frac{1 \times 1}{2 \times 3} = \frac{1}{6}

    11 times 11 is 11, and 22 times 33 is 66.

  3. State the exact answer

    16\frac{1}{6}

    A half of a third is one sixth — already in simplest form.

Answer
16\frac{1}{6}
Question 4
1 markeasy
Simplify 2π+5π2\pi + 5\pi.

Worked solution

  1. Treat pi like a unit

    2π+5π2\pi + 5\pi

    Multiples of pi collect together just like terms in algebra: 22 lots of pi plus 55 lots of pi.

  2. Add the multipliers

    2+5=72 + 5 = 7

    Add the numbers in front of pi.

  3. State the exact answer

    2π+5π=7π2\pi + 5\pi = 7\pi

    Seven lots of pi, written 7π7\pi — an exact value, unlike any decimal for pi.

Answer
7π7\pi
Question 5
1 markeasy
Simplify 10π4π10\pi - 4\pi.

Worked solution

  1. Treat pi like a unit

    10π4π10\pi - 4\pi

    Ten lots of pi minus four lots of pi — collect the terms.

  2. Subtract the multipliers

    104=610 - 4 = 6

    Subtract the numbers in front of pi.

  3. State the exact answer

    10π4π=6π10\pi - 4\pi = 6\pi

    Six lots of pi, written 6π6\pi.

Answer
6π6\pi

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