Factorising quadratics Worked Solutions — GCSE Maths

Fully worked, step-by-step solutions to GCSE Factorising quadratics questions. See exactly how to solve problems on common factor, factorising, factorising quadratics, factor pairs.

common factorfactorisingfactorising quadraticsfactor pairsdifference of two squaresperfect square
GCSE Foundation70 questionsStep-by-step solutions
Question 1
1 markeasy
Factorise 2x+62x + 6.

Worked solution

  1. Find the highest common factor

    HCF=2\text{HCF} = 2

    Every term divides by 2.

  2. Divide each term by 2

    2x÷2=x,6÷2=32x \div 2 = x,\quad 6 \div 2 = 3

    Write what is left inside the bracket.

  3. Write the factorised form

    2(x+3)2(x + 3)

    Check: 2×x=2x2 \times x = 2x and 2×3=62 \times 3 = 6, giving 2x+62x + 6.

Answer
2(x+3)2(x + 3)
Question 2
1 markeasy
Factorise 3x+123x + 12.

Worked solution

  1. Find the highest common factor

    HCF=3\text{HCF} = 3

    Every term divides by 3.

  2. Divide each term by 3

    3x÷3=x,12÷3=43x \div 3 = x,\quad 12 \div 3 = 4

    Write what is left inside the bracket.

  3. Write the factorised form

    3(x+4)3(x + 4)

    Check: 3×x=3x3 \times x = 3x and 3×4=123 \times 4 = 12.

Answer
3(x+4)3(x + 4)
Question 3
1 markeasy
Factorise 5x155x - 15.

Worked solution

  1. Find the highest common factor

    HCF=5\text{HCF} = 5

    Every term divides by 5.

  2. Divide each term by 5

    5x÷5=x,15÷5=35x \div 5 = x,\quad 15 \div 5 = 3

    Write what is left inside the bracket.

  3. Write the factorised form

    5(x3)5(x - 3)

    Check: 5 ×\times x=5xx = 5x and 5 ×\times (3)=15(-3) = -15.

Answer
5(x3)5(x - 3)
Question 4
1 markeasy
Factorise x2+3xx^2 + 3x.

Worked solution

  1. Find the common factor

    each term contains x\text{each term contains } x

    Both terms have a factor of x.

  2. Take out x

    x(x+3)x(x + 3)

    Divide each term by x and write x outside.

  3. Check by expanding

    x(x+3)x(x + 3)

    Check: x ×\times x=x2x = x^2 and x ×\times 3=3x3 = 3x.

Answer
x(x+3)x(x + 3)
Question 5
1 markeasy
Factorise x27xx^2 - 7x.

Worked solution

  1. Find the common factor

    each term contains x\text{each term contains } x

    Both terms have a factor of x.

  2. Take out x

    x(x7)x(x - 7)

    Divide each term by x and write x outside.

  3. Check by expanding

    x(x7)x(x - 7)

    Check: x ×\times x=x2x = x^2 and x ×\times (7)=7x(-7) = -7x.

Answer
x(x7)x(x - 7)

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