Factorising ax2 + bx + c Worked Solutions — GCSE Maths

Fully worked, step-by-step solutions to GCSE Factorising ax2 + bx + c questions. See exactly how to solve problems on factorising quadratics, AC method, splitting the middle term, common factor.

factorising quadraticsAC methodsplitting the middle termcommon factordifference of two squaresfactorising
GCSE Higher70 questionsStep-by-step solutions
Question 1
1 markeasy
Factorise 2x2+3x+12x^2 + 3x + 1.

Worked solution

  1. Set up the brackets

    2x2+3x+1=(2x  )(x  )2x^2 + 3x + 1 = (2x\ \ )(x\ \ )

    The x2x^2 term is 2x2=2x×x2x^2 = 2x \times x, so each bracket starts with 2x2x and xx.

  2. Find the number terms

    1×1=1,2x+1x=3x1 \times 1 = 1, \quad 2x + 1x = 3x

    The two numbers must multiply to give 11 and, after cross-multiplying, give the middle term 3x3x. Those numbers are 11 and 11.

  3. Write the factorised form

    (2x+1)(x+1)(2x + 1)(x + 1)

    So 2x2+3x+1=(2x+1)(x+1)2x^2 + 3x + 1 = (2x + 1)(x + 1). Expanding (2x+1)(x+1)(2x + 1)(x + 1) returns 2x2+3x+12x^2 + 3x + 1, confirming the factorisation.

Answer
(2x+1)(x+1)(2x + 1)(x + 1)
Question 2
1 markeasy
Which of the following is the correct factorisation of 2x2+5x+22x^2 + 5x + 2?

Worked solution

  1. Set up the brackets

    2x2+5x+2=(2x  )(x  )2x^2 + 5x + 2 = (2x\ \ )(x\ \ )

    The x2x^2 term is 2x2=2x×x2x^2 = 2x \times x, so each bracket starts with 2x2x and xx.

  2. Find the number terms

    1×2=2,4x+1x=5x1 \times 2 = 2, \quad 4x + 1x = 5x

    The two numbers must multiply to give 22 and, after cross-multiplying, give the middle term 5x5x. Those numbers are 11 and 22.

  3. Write the factorised form

    (2x+1)(x+2)(2x + 1)(x + 2)

    So 2x2+5x+2=(2x+1)(x+2)2x^2 + 5x + 2 = (2x + 1)(x + 2). Expanding (2x+1)(x+2)(2x + 1)(x + 2) returns 2x2+5x+22x^2 + 5x + 2, confirming the factorisation.

Answer
(2x+1)(x+2)(2x + 1)(x + 2)
Question 3
1 markeasy
Factorise 2x2+7x+32x^2 + 7x + 3.

Worked solution

  1. Set up the brackets

    2x2+7x+3=(2x  )(x  )2x^2 + 7x + 3 = (2x\ \ )(x\ \ )

    The x2x^2 term is 2x2=2x×x2x^2 = 2x \times x, so each bracket starts with 2x2x and xx.

  2. Find the number terms

    1×3=3,6x+1x=7x1 \times 3 = 3, \quad 6x + 1x = 7x

    The two numbers must multiply to give 33 and, after cross-multiplying, give the middle term 7x7x. Those numbers are 11 and 33.

  3. Write the factorised form

    (2x+1)(x+3)(2x + 1)(x + 3)

    So 2x2+7x+3=(2x+1)(x+3)2x^2 + 7x + 3 = (2x + 1)(x + 3). Expanding (2x+1)(x+3)(2x + 1)(x + 3) returns 2x2+7x+32x^2 + 7x + 3, confirming the factorisation.

Answer
(2x+1)(x+3)(2x + 1)(x + 3)
Question 4
1 markeasy
Factorise 3x2+4x+13x^2 + 4x + 1.

Worked solution

  1. Set up the brackets

    3x2+4x+1=(3x  )(x  )3x^2 + 4x + 1 = (3x\ \ )(x\ \ )

    The x2x^2 term is 3x2=3x×x3x^2 = 3x \times x, so each bracket starts with 3x3x and xx.

  2. Find the number terms

    1×1=1,3x+1x=4x1 \times 1 = 1, \quad 3x + 1x = 4x

    The two numbers must multiply to give 11 and, after cross-multiplying, give the middle term 4x4x. Those numbers are 11 and 11.

  3. Write the factorised form

    (3x+1)(x+1)(3x + 1)(x + 1)

    So 3x2+4x+1=(3x+1)(x+1)3x^2 + 4x + 1 = (3x + 1)(x + 1). Expanding (3x+1)(x+1)(3x + 1)(x + 1) returns 3x2+4x+13x^2 + 4x + 1, confirming the factorisation.

Answer
(3x+1)(x+1)(3x + 1)(x + 1)
Question 5
1 markeasy
Factorise 2x2+7x+52x^2 + 7x + 5.

Worked solution

  1. Set up the brackets

    2x2+7x+5=(2x  )(x  )2x^2 + 7x + 5 = (2x\ \ )(x\ \ )

    The x2x^2 term is 2x2=2x×x2x^2 = 2x \times x, so each bracket starts with 2x2x and xx.

  2. Find the number terms

    5×1=5,2x+5x=7x5 \times 1 = 5, \quad 2x + 5x = 7x

    The two numbers must multiply to give 55 and, after cross-multiplying, give the middle term 7x7x. Those numbers are 55 and 11.

  3. Write the factorised form

    (2x+5)(x+1)(2x + 5)(x + 1)

    So 2x2+7x+5=(2x+5)(x+1)2x^2 + 7x + 5 = (2x + 5)(x + 1). Expanding (2x+5)(x+1)(2x + 5)(x + 1) returns 2x2+7x+52x^2 + 7x + 5, confirming the factorisation.

Answer
(2x+5)(x+1)(2x + 5)(x + 1)

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