Inequalities Worked Solutions — A-Level Maths

Fully worked, step-by-step solutions to A-Level Inequalities questions. See exactly how to solve problems on linear inequality, solve, divide by negative, unknown both sides.

linear inequalitysolvedivide by negativeunknown both sidesbracketsquadratic inequality
A-Level70 questionsStep-by-step solutions
Question 1
2 markseasy
Solve the inequality 3x+4>193x + 4 > 19.

Worked solution

  1. Subtract 4 from both sides

    3x+44>194    3x>153x + 4 - 4 > 19 - 4 \;\Rightarrow\; 3x > 15

    We want the term with x on its own, so we undo the +4 by subtracting 4 from each side. Because we are only adding or subtracting, the inequality sign stays exactly the same.

  2. Divide both sides by 3

    3x3>153    x>5\frac{3x}{3} > \frac{15}{3} \;\Rightarrow\; x > 5

    Now we undo the multiplication by 3 by dividing both sides by 3. We are dividing by a positive number, so the inequality sign does not flip.

  3. State the solution

    x>5x > 5

    So every number bigger than 5 makes the inequality true. On the number line we use an open circle at 5 to show 5 itself is not included.

Answer
x>5x > 5
Question 2
2 markseasy
Solve the inequality 5x7185x - 7 \le 18.

Worked solution

  1. Add 7 to both sides

    5x7+718+7    5x255x - 7 + 7 \le 18 + 7 \;\Rightarrow\; 5x \le 25

    To get the x-term by itself we undo the -7 by adding 7 to both sides. Adding the same amount to each side never changes the direction of the inequality.

  2. Divide both sides by 5

    5x5255    x5\frac{5x}{5} \le \frac{25}{5} \;\Rightarrow\; x \le 5

    We divide by 5 to leave x alone. Since 5 is positive, the sign stays as 'less than or equal to'.

  3. State the solution

    x5x \le 5

    All values up to and including 5 work. We show this with a filled (solid) circle at 5 because 5 is included.

Answer
x5x \le 5
Question 3
2 markseasy
Solve the inequality 2x>8-2x > 8.

Worked solution

  1. Identify what to divide by

    2x>8-2x > 8

    The x is multiplied by -2, so to free it we must divide both sides by -2. This is the key step where care is needed.

  2. Divide by -2 and flip the sign

    2x2    <    82    x<4\frac{-2x}{-2} \;\;\boxed{<}\;\; \frac{8}{-2} \;\Rightarrow\; x < -4

    Whenever you multiply or divide an inequality by a NEGATIVE number, you must reverse the inequality sign. So '>' becomes '<'.

  3. State the solution

    x<4x < -4

    The answer is all numbers less than -4. Forgetting to flip the sign here is the most common mistake, so always check the direction.

Answer
x<4x < -4
Question 4
2 markseasy
Solve the inequality 4x+1<2x+94x + 1 < 2x + 9.

Worked solution

  1. Subtract 2x from both sides

    4x+12x<2x+92x    2x+1<94x + 1 - 2x < 2x + 9 - 2x \;\Rightarrow\; 2x + 1 < 9

    There are x-terms on both sides, so gather them on one side. Taking 2x from each side keeps the inequality balanced and the sign unchanged.

  2. Subtract 1 from both sides

    2x+11<91    2x<82x + 1 - 1 < 9 - 1 \;\Rightarrow\; 2x < 8

    Now move the number term away from the x-term by subtracting 1 from both sides.

  3. Divide both sides by 2

    x<4x < 4

    Dividing by the positive number 2 finishes the job and the sign stays the same.

Answer
x<4x < 4
Question 5
2 markseasy
Solve the inequality 3(x2)93(x - 2) \ge 9.

Worked solution

  1. Expand the bracket

    3x693x - 6 \ge 9

    Multiply everything inside the bracket by 3: 3 times x is 3x and 3 times -2 is -6. This clears the bracket so we can solve normally.

  2. Add 6 to both sides

    3x153x \ge 15

    Undo the -6 by adding 6 to both sides to isolate the x-term.

  3. Divide both sides by 3

    x5x \ge 5

    Dividing by the positive number 3 gives the final answer, with the sign kept as 'greater than or equal to'.

Answer
x5x \ge 5

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