Find the y-intercept
x=0: y=2−e0=2−1=1 Setting x=0 gives y=1, so the curve passes through (0,1).
Find the asymptote
x→∞: e−x→0, y→2 As x grows, e−x→0, so y rises towards the asymptote y=2.
Check behaviour for negative x
x→−∞: e−x→∞, y→−∞ For very negative x, e−x is huge, so y dives downwards; the curve is increasing overall.
List the features to match
intercept, direction, asymptote To choose the right graph we make a short checklist of the curve's key features: where it crosses the y-axis, whether it rises or falls, and the position of its asymptote.
Check the y-intercept feature
correct y-intercept The correct graph must cross the y-axis at the height we calculated above. This rules out any option with the wrong starting point.
Check the direction feature
correct increasing/decreasing shape The correct graph must rise or fall in the same way as our curve. A curve going the wrong way indicates a reflection, so it can be rejected.
Check the asymptote feature
correct horizontal asymptote The correct graph must flatten out towards the same horizontal line we found. An option with a different asymptote has been shifted vertically and is wrong.
Reject the reflected graph
reject reflection One distractor is the curve reflected in an axis, so it goes the wrong way. Because its direction disagrees with our analysis, we reject it.
Reject the vertically shifted graph
reject vertical shift Another distractor has been moved up or down, giving the wrong asymptote and intercept. This does not match, so we reject it.
Reject the horizontally shifted graph
reject horizontal shift A further distractor is shifted left or right, so its key point sits at the wrong x-value. We reject it too.
Reject the non-exponential graph
reject wrong type One option is not even the right type of curve (for example a straight line), so it cannot be an exponential graph and is rejected.
Confirm only one graph fits
one graph matches all features Exactly one graph has the correct intercept, direction and asymptote all together, which pins down the answer.
Match to the correct graph
Increasing curve through (0,1) with asymptote y=2. We select the graph that matches every feature in our checklist.
Double-check with a sample point
verify one plotted point As a final check we test one easy point on the chosen graph and confirm it agrees with our equation. It does, so the choice is secure.
Find the x-intercept
y=0: e−x=2 ⇒ x=−ln2≈−0.69 The curve crosses the x-axis where e−x=2, i.e. x=−ln2, just left of the origin.